Explanation:
by staying late to help people aswell as being their and putting full effort into it
because the others arent helping they are only only just reminding
Answer:
#include <iostream>
using namespace std;
int main() {
int currentYear = 2020;
int myCurrentAge = 23;
int myNewAge=myCurrentAge+(2050-currentYear);
cout << "My Current Age is " << myCurrentAge << endl;
cout << "I will be " << myNewAge << " in 2050." << endl;
}
Explanation:
- Initialize the currentYear with 2020 and myCurrentAge with 23.
- Add myCurrentAge with the the result of (2015 - currentYear) and assign this result to myNewAge variable.
- Finally display my current age and after that display the new age in 2050.
Output:
My Current Age is 23
I will be 53 in 2050.
Answer:
They protect patient medical records im pretty sure
Explanation:
Answer:
def max_n(arr, n):
arr.sort()
i = len(arr)-n
return arr[i:]
Explanation:
Define a function called max_n that takes two parameters, an array and an integer
Sort the array
In order to get the last n largest values, we need to slice the array. To do that we need a starting point. Our starting point of slicing will be the "lentgh of the array - n". That means, if we start slicing from that index to the last in the sorted array, we will get the last n largest values.
Assume array is 10, 2, 444, 91 initially.
When we sort it, it becomes 2, 10, 91, 444
Now let's say we want last 2 largest values, our sliced array index should start from 2 and go until the end
i = 4 - 2 = 2 → arr[2:] will return us 91 and 444
<span>The answer should be "translucent" ... </span>
