Answer:
The answer is 18,700
Step-by-step explanation:
if you add 9,500+ 9,000 you get 18,500 add 200 and your answer is 18,700
Step-by-step explanation:
let the first-day ride be x
Then the second-day ride will be
=1.5
x
The third-day ride will be=1.5(1.5x)
The Fourth-day ride will be=1.5*1.5(1.5x)
hence for the four days the distance covered is
65=x+1.5x+1.5*1.5x+1.5*1.5*1.5x
65=x+1.5x+2.25x+3.375x
65=8.125x
divide both sides by 8.125 we have
x=65/8.125
x=8mile
the first-day ride be x=8miles
the second-day ride will be
=1.5
x
=1.5*8= 12miles
The third-day ride will be=1.5(1.5x) = 18miles
The Fourth-day ride will be=1.5*1.5(1.5x) = 27miles
Answer:
The answer is C
Step-by-step explanation:
If you count the rise over un to calculate your slope, which in this case it is drop 2 and to the right 3, that gives you the slope of -2/3
Answer:
<u><em>C. </em></u>
<u><em> cm</em></u>
Step-by-step explanation:
<u><em>First, we can start out by stating that this is a </em></u><u><em>right triangle</em></u><u><em>, since </em></u><u><em>it has a right angle</em></u><u><em>, shown by the marker square in the corner of the triangle. </em></u><u><em>The x part, is called the hypotenuse</em></u><u><em>. When finding the value of the hypotenuse, we use a thing called the </em></u><u><em>Pythagorean Theorem.</em></u><u><em> This theorem is :</em></u>
<u><em>a^2 + b^2 = c^2</em></u>
<u><em>a is one side length, and b is the other. c is the hypotenuse.</em></u><u><em> To find x, the hypotenuse, we simply </em></u><u><em>plug in the values, and solve.</em></u>
<u><em>8^2 + 5^2 = c^2</em></u>
<u><em>64 + 25 = c^2</em></u>
<u><em>89 = c^2</em></u>
<u><em>To get c alone, we do the </em></u><u><em>square root of 89.</em></u>
<u><em></em></u>
<u><em> = c</em></u>
<u><em>9.43398113 = c</em></u>
<u><em>So, the answer is </em></u><u><em>C. </em></u>
<u><em> cm</em></u>
Let's assume that the statement "if n^2 is odd, then is odd" is false. That would mean "n^2 is odd" leads to "n is even"
Suppose n is even. That means n = 2k where k is any integer.
Square both sides
n = 2k
n^2 = (2k)^2
n^2 = 4k^2
n^2 = 2*(2k^2)
The expression 2(2k^2) is in the form 2m where m is an integer (m = 2k^2) which shows us that n^2 is also even.
So this contradicts the initial statement which forces n to be odd.