All categories

2 years ago

Please help me please

Mathematics

1 answer:

Volgvan2 years ago

3 0

The answer is 1.29k = t

You might be interested in

Hi can someone help with this question? Thanks!!!

aleksandrvk [35]

Sorry I cant help you with that good luck with that.

4 0

2 years ago

Which shows the correct way to convert 5 ounces to pounds

Daniel [21]

There are 16 ounces in 1 lb.

divide however many ounces you have by 16 ounces. 

34 oz / 16 oz = 2lbs 2 oz

7 0

2 years ago

Read 2 more answers

Find x and y please help ! tyyyy

garri49 [273]

Answer:

x = 41* & y = 90.

Step-by-step explanation:

Since we know that the figure is a right triangle, we can solve for y easily, as 90+y = 180

y = 90

to solve for x, we have 49+90+x, since the angle that makes up the left side is perpendicular to the triangle,

so 139+x = 180

x = 180-139

x = 41

8 0

1 year ago

Convert this to degrees <img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7B20%7D%20%5Cpi" id="TexFormula1" title=" \frac{3

dezoksy [38]

Here is the answer. Just click on the photo below. Hope this helps!

8 0

2 years ago

Find all values of m so that the function y= e^mx is a solution of the given differential equation.

son4ous [18]

Answer:

m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.

Step-by-step explanation:

To determine all values of m so that the function y= e^mx is a solution of the given differential equation.

First, we will find y'.

From, y= e^mx

$y = e^{mx}$

But, $y' = \frac{d}{dx}y$

Hence,

$y' = \frac{d}{dx}e^{mx}\\$

∴ $y' = me^{mx}$

Now, we will put the values of y' and y into the given differential equation y' + 2y =0

From the question,

$y = e^{mx}$

and

$y' = me^{mx}$

Then, $y' + 2y =0\\$ becomes

$me^{mx} + 2(e^{mx}) = 0$

Then, $me^{mx} = - 2(e^{mx}) \\\\$

$m = \frac{-2(e^{mx}) }{e^{mx} } \\$

∴ $m = -2$

Hence, m = - 2 is the value of m that the function y= e^mx is a solution of the differential equation, y' + 2y = 0.

3 0

2 years ago