Train X is traveling at a constant speed of 30 miles per hour and Train Y is traveling at a constant speed of 40 miles per hour. If the two trains are traveling in the same direction along the same route but Train X is 25 miles ahead of Train Y, how many hours will it be until Train Y is 10 miles ahead of Train X?
2 answers:
Answer:
3.5 hours
Step-by-step explanation:
Speed of train X=30 mph
Speed of train Y=40 mph
Relative speed When the two trains travelling in same direction
Relative speed=40-30=10 mph
Total distance =25+10=35 miles
We have to find the time when train Y is 10 miles ahead of train X.
We know that
Time=
Using the formula
Then, we get
Time=
Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.
Answer:
3.5 hours.
Step-by-step explanation:
When train Y is at position 0 train X is at position 25.
Speed = distance / time.
Suppose the distance travelled by train X before Train Y catches up with him is x miles.
Then we have the system
30 = x/ t
40 = (x + 25) / t where t is the time in hours.
x = 30t plug this into the second equation
40 = ( 30t + 25) / t
40t = 30t + 25
10t = 25
t = 2.5 hours.
Now the time taken for train Y to get 10 miles ahead is calculated as follows:
Combined speed = 40 - 30 = 10 mph.
so 10 = 10/t
t = 1 hours.
Answer is 3.5 hours.
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