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a_sh-v [17]
4 years ago
6

I will give brainliest!! please help!!!

Mathematics
1 answer:
hram777 [196]4 years ago
6 0

Answer:

Yes

No

Yes

No

No

Im pretty sure its like that dont hate if i get one wrong

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A supermarket has two customers waiting to pay for their purchases at counter I and one customer waiting to pay at counter II. L
Pachacha [2.7K]

Answer:

b. 0.864

Step-by-step explanation:

Let's start defining the random variables.

Y1 : ''Number of customers who spend more than $50 on groceries at counter 1''

Y2 : ''Number of customers who spend more than $50 on groceries at counter 2''

If X is a binomial random variable, the probability function for X is :

P(X=x)=(nCx)p^{x}(1-p)^{n-x}

Where P(X=x) is the probability of the random variable X to assume the value x

nCx is the combinatorial number define as :

nCx=\frac{n!}{x!(n-x)!}

n is the number of independent Bernoulli experiments taking place

And p is the success probability.

In counter I :

Y1 ~ Bi (n,p)

Y1 ~ Bi(2,0.2)

P(Y1=y1)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}

With y1 ∈ {0,1,2}

And P( Y1 = y1 ) = 0 with y1 ∉ {0,1,2}

In counter II :

Y2 ~ Bi (n,p)

Y2 ~ Bi (1,0.3)

P(Y2=y2)=(1Cy2)(0.3)^{y2}(0.7)^{1-y2}

With y2 ∈ {0,1}

And P( Y2 = y2 ) = 0 with y2 ∉ {0,1}

(1Cy2) with y2 = 0 and y2 = 1 is equal to 1 so the probability function for Y2 is :

P(Y2=y2)=(0.3)^{y2}(0.7)^{1-y2}

Y1 and Y2 are independent so the joint probability distribution is the product of the Y1 probability function and the Y2 probability function.

P(Y1=y1,Y2=y2)=P(Y1=y1).P(Y2=y2)

P(Y1=y1,Y2=y2)=(2Cy1)(0.2)^{y1}(0.8)^{2-y1}(0.3)^{y2}(0.7)^{1-y2}

With y1 ∈ {0,1,2} and y2 ∈ {0,1}

P( Y1 = y1 , Y2 = y2) = 0 when y1 ∉ {0,1,2} or y2 ∉ {0,1}

b. Not more than one of three customers will spend more than $50 can mathematically be expressed as :

Y1 + Y2 \leq 1

Y1 + Y2\leq 1 when Y1 = 0 and Y2 = 0 , when Y1 = 1 and Y2 = 0 and finally when Y1 = 0 and Y2 = 1

To calculate P(Y1+Y2\leq 1) we must sume all the probabilities that satisfy the equation :

P(Y1+Y2\leq 1)=P(Y1=0,Y2=0)+P(Y1=1,Y2=0)+P(Y1=0,Y2=1)

P(Y1=0,Y2=0)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{0}(0.7)^{1-0}=(0.8)^{2}(0.7)=0.448

P(Y1=1,Y2=0)=(2C1)(0.2)^{1}(0.8)^{2-1}(0.3)^{0}(0.7)^{1-0}=2(0.2)(0.8)(0.7)=0.224

P(Y1=0,Y2=1)=(2C0)(0.2)^{0}(0.8)^{2-0}(0.3)^{1}(0.7)^{1-1}=(0.8)^{2}(0.3)=0.192

P(Y1+Y2\leq 1)=0.448+0.224+0.192=0.864\\P(Y1+Y2\leq 1)=0.864

7 0
3 years ago
What are the graphs of y=sinx and y=cosx in the interval from -2 pi to 2 pi?
g100num [7]
I used Excel to create the tables and the graphs.

I attached both the tables and the graphs.


You should replace the numbers of the x-axis (in both graphs) by the numbers as a fraction of pi. Those numbers are also included in the table, so you should not have problems with that.


Open and see tha file attached with the answer to your question..
Download pdf
5 0
3 years ago
Write an equation to represent the following description. Seventeen more than eight times a number is −6.
german
8x + 17 = -6


(you can use a different variable to replace x if you need to :D)
5 0
3 years ago
Someone, please help me with this problem, please
prohojiy [21]
Altérnate exterior
same side exterior
vertical angles
corresponding angles
alternate interior
same side interior
straight angles
5 0
3 years ago
Passing through(-1,8) and parallel to the line whose equation is 8x-9y-2=0
notka56 [123]
<h3>Answer:</h3>

y = 8/9x + 80/9

<h3>Step-by-step explanation:</h3>

<u>We are given;</u>

  • Equation of a line as 8x -9y -2 = 0
  • Coordinates (-1,8)

We are required to determine the equation of a line parallel to the given line and passing through a point (-1,8)

<h3>Step 1: Determine the Gradient of the given line </h3>
  • When an equation is written in the form y = mx + c, m is the gradient.
  • Therefore; we could write the equation 8x -9y -2 = 0 in the form of  y= mx + c

9y = 8x -2

y = 8/9x - 2/9

Therefore, the slope, m = 8/9

<h3>Step 2: Determine the equation of the line</h3>
  • We need to know that parallel lines have the same gradient
  • Therefore, the slope of the line in question is 8/9
  • It passes through a point (-1, 8)

We can therefore, determine the equation;

Taking another point, (x,y)

\frac{y-8}{x+1} = \frac{8}{9}

9(y-8) = 8(x+1)

9y - 72 = 8x + 8

 9y = 8x + 8 +72

 9y = 8x + 80

  y = 8/9x + 80/9

Therefore, the equation of the line is y = 8/9x + 80/9

4 0
4 years ago
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