Answer:
The numbers are 12, 21.
Step-by-step explanation:
x+(x+9)=33
x+x+9=33
2x+9=33
2x=33-9
2x=24
x=24/2
x=12
--------
x+9=12+9=21
Please mark me as Brainliest if you're satisfied with the answer.
16.7 is the answer rounded to the nearest tenth.
Answer: a) zeros: x = {0, 4, -2}
b) as x → ∞, y → ∞
as x → -∞, y → ∞
<u>Step-by-step explanation:</u>
I think you mean (a) find the zeros and (b) describe the end behavior
(a) Find the zeros by setting each factor equal to zero and solving for x:
x (x - 4) (x + 2)⁴ = 0
- x = 0 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis
- x = 4 Multiplicity of 1 --> odd multiplicity so it crosses the x-axis
- x = -2 <u>Multiplicity of 4 </u> --> even multiplicity so it touches the x-axis
Degree = 6
(b) End behavior is determined by the following two criteria:
- Sign of Leading Coefficient (Right side): Positive is ↑, Negative is ↓
- Degree (Left side): Even is same direction as right side, Odd is opposite direction of right side
Sign of the leading coefficient is Positive so right side goes UP
as x → ∞, y → ∞
Degree of 6 is Even so Left side is the same direction as right (UP)
as x → -∞, y → ∞
Answer: 0.75
Step-by-step explanation:
Given : Interval for uniform distribution : [0 minute, 5 minutes]
The probability density function will be :-
The probability that a given class period runs between 50.75 and 51.25 minutes is given by :-
![P(x>1.25)=\int^{5}_{1.25}f(x)\ dx\\\\=(0.2)[x]^{5}_{1.25}\\\\=(0.2)(5-1.25)=0.75](https://tex.z-dn.net/?f=P%28x%3E1.25%29%3D%5Cint%5E%7B5%7D_%7B1.25%7Df%28x%29%5C%20dx%5C%5C%5C%5C%3D%280.2%29%5Bx%5D%5E%7B5%7D_%7B1.25%7D%5C%5C%5C%5C%3D%280.2%29%285-1.25%29%3D0.75)
Hence, the probability that a randomly selected passenger has a waiting time greater than 1.25 minutes = 0.75
