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Sunny_sXe [5.5K]
2 years ago
11

Need help!!! I dont get it

Mathematics
1 answer:
lesya692 [45]2 years ago
7 0

Answer:

4/3π - √3

Step-by-step explanation:

Pie piece of circle is area of circle x portion of circle

πr²*x/360 = π(2)²*120/360 = 4/3π

Then you must subract the non-right triangle area

1/2ab sin C = 1/2(2)(2) sin 120 = 2 * √3/2 = √3

4/3π - √3

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The zeroes of f(x) = x3 + 3x2 + 2x are <br> .
Vaselesa [24]

The zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2

<h3>How to determine the zeros of the function?</h3>

The function is given as:

f(x) = x^3 + 3x^2 + 2x

Factor out x in the above function

f(x) = x(x^2 + 3x + 2)

Set the function to 0

x(x^2 + 3x + 2) = 0

Factorize the expression in the bracket

x(x + 1)(x + 2) = 0

Split the expression

x = 0, x + 1 = 0 and x + 2 = 0

Solve for x

x = 0, x = -1 and x = -2

Hence, the zeros of the function f(x) = x^3 + 3x^2 + 2x are x = 0, x = -1 and x = -2

Read more about zeros of function at

brainly.com/question/20896994

#SPJ1

7 0
1 year ago
Read 2 more answers
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