Answer:
Step-by-step explanation:
For each component, there are only two possible outcomes. Either it fails, or it does not. The components are independent. We want to know how many outcomes until r failures. The expected value is given by
In which r is the number of failures we want and p is the probability of a failure.
In this problem, we have that:
r = 1 because we want the first failed unit.
![p = 0.4[\tex]So[tex]E = \frac{r}{p} = \frac{1}{0.4} = 2.5](https://tex.z-dn.net/?f=p%20%3D%200.4%5B%5Ctex%5D%3C%2Fp%3E%3Cp%3ESo%3C%2Fp%3E%3Cp%3E%5Btex%5DE%20%3D%20%5Cfrac%7Br%7D%7Bp%7D%20%3D%20%5Cfrac%7B1%7D%7B0.4%7D%20%3D%202.5)
The expected number of systems inspected until the first failed unit is 2.5
Im not sure sorry, I hope you find your answer
1)5 2)6 3)17 because h(x)+k(x)=3x-1
Answer:
-37- -47=-10
Step-by-step explanation:
Answer:
#Answer: 3 Step-by-step explanation: Common sence 8 months ago 3 0 Answer: There are 3 necklace and bracelet sets she can make . Step-by-step explanation: Since we have given that Length of wire she used to make a necklace is given by Length of wire she used to make a bracelet is given by Total length of wire she is used in all is given by Now, we calculate number of necklace and bracelet sets she can make , So, So, there are 3 necklace
