Question

If x equals negative 2 and y equals the square root of 12, then begin expression . . . 2 times the quantity . . . 3 times x raised to the third power, plus 2 times y raised to the second power . . . end expression . . . equals

Answer 1

I don't understand your question, expressions do not end with equal signs. Or are you just asking how to write the expression?

2*((3*x)^3)+2(y^2)    then simply replace the x with "-2" and y with "sqrt(12)"
2*(-2)^3+2(12)
-16+24
8

Answer 2

Answer:

The value of given expression at x = -2 and y = $\sqrt{12}$ is 0

Step-by-step explanation:Given expression : 2 times the quantity 3 times x raised to the third power, plus 2 times y raised to the second power .

WE have to evaluate the value of given expression at  x equals negative 2 and y equals the square root of 12 that at x = -2 and y = $\sqrt{12}$

Given expression can be represented mathematically as,

$2(3x^3+2y^2)$

First we simplify the given expression,

$\Rightarrow 2(3x^3+2y^2)$

Put  x = -2 and y = $\sqrt{12}$ , we get

$\Rightarrow 2(3(-2)^3+2(\sqrt{12})^2)$

On simplifying, we get,

$\Rightarrow 2(3(-8)+2(12)$

$\Rightarrow 2(-24+24)$

$\Rightarrow 2(0)$

$\Rightarrow 0$

Thus, the value of given expression at x = -2 and y = $\sqrt{12}$ is 0