Answer:
where is the paragraph?
Step-by-step explanation:
An applicable equation of a vertical parabola in vertex form is:
y-k = a(x-h)^2
Let x=2, y=4, h=-1 and k=-1, where (h,k) is the vertex. Then,
4-(-1) = a(2-[-1])^2, which becomes 5 = a(9). Therefore, a = 5/9, and the
equation of the parabola is
y+1 = (5/9)(x+1)
Differentiate:
-5×2(xe^x^2)y-5e^x^2dy/dx=1
-5e^x^2(2xy+y´)=1
When x=-5, y=0:
-5e²⁵y´=1, so y´(-5)=-eˉ²⁵/5
Answer:
The quandrants on a grap are basically the groups on the graph like quadrant I ,II ,III , and IV hope that helps
Step-by-step explanation:
Answer:
Step-by-step explanation:
120/6.4=20
It will take her 20 days
