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kramer
3 years ago
14

Round 0.76581 to the specified number of decimal places which is 3

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

0.766 is the answer for the question

Dennis_Churaev [7]3 years ago
7 0

Answer:

The answer is 0.766 because the 8 makes it round up.

Step-by-step explanation:

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Can someone help me please.
34kurt

Answer:

c ?

Step-by-step explanation:

7 0
3 years ago
What are the restrictions for y <br> X=10/5+y
Naya [18.7K]

Answer:

y\ne-5

Step-by-step explanation:

So you have the equation:

  x=\frac{10}{5+y}. As you may know, you cannot divide by 0, so y has to be restricted in a way that the denominator is never equal to 0. So to find when y makes the denominator 0, simply set the denominator equal to 0, and solve for y. This gives you the equation: 5+y = 0, y=-5. So the y value CANNOT be equal to -5. Because it makes the denominator 0. so y\ne-5 would be the restriction.

7 0
2 years ago
8 is subtracted from twice a number
ankoles [38]

Answer:

2x-8

Step-by-step explanation:

The word "from" tells you that the first part of the sentence should be at the back of the equation because you're taking from the product of 2 times a number, the number is unknown so it is known as "x."

5 0
3 years ago
On a number line, graph two different points that have the same absolute value.
Over [174]
The absolute value of 3 and the absolute value of negative 3. they have the same distance from 0
8 0
3 years ago
Read 2 more answers
Find the inner product for (7, 2) * (0, -2) and state whether the vectors are perpendicular.
Andrews [41]

Answer: A

Step-by-step explanation:

To find the inner product of two vectors (a,b) and (c,d) you would use the equation (a * c) + (b * d)

So for (7,2) and (0,-2) the inner product would be

(7 * 0) + (2 * -2)

= 4

The vectors are only perpendicular when the inner product is equal to 0. Since it is equal to -4 in this case, the vectors are not perpendicular.

A -4; no

3 0
3 years ago
Read 2 more answers
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