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kramer
3 years ago
14

Round 0.76581 to the specified number of decimal places which is 3

Mathematics
2 answers:
anzhelika [568]3 years ago
7 0

Answer:

0.766 is the answer for the question

Dennis_Churaev [7]3 years ago
7 0

Answer:

The answer is 0.766 because the 8 makes it round up.

Step-by-step explanation:

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PLEASE HELP ME!!!!! Factor completely b^4 − b^3 + b − 1
Afina-wow [57]
<span>b^4 − b^3 + b − 1
=(</span><span>b^4 − b^3) + (b − 1)
= b^3(b - 1) + (b - 1)
=(b - 1)(b^3 + 1)</span>
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3 years ago
I’ll mark brainliest !!<br> Plz help
saveliy_v [14]

Answer:

3rd option

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Gio is solving the quadratic equation by completing the square 5x^2+15x-4=0 What's should gio do first?
Softa [21]
Gio should for sure devide everything by ^2 and then combine like terms.
5 1
3 years ago
Please help with this one
anyanavicka [17]

Ok this inequality tells you the number of devices you can have before the new plan costs more than the old plan. The new plan expression is $4.50x + $94m =  y ( total cost). The old plan is $175m = y (total cost). You can see m (number of months) in both equations, you don't need it this time since we're going to to compare both to one month. Since they're both equal to y you can make them equal to each other. $4.50x + $94 = $175. Now you want to figure when the new plan is less than the old plan you switch the equal sign for a less than sign. $4.50x + $94 < $175; this will help you find the inequality you want. From there just use algebraic steps to find that x has to less than 18 or

x < 18.

3 0
3 years ago
2 u + 12 &lt; 23<br> 0,1 d + 8 &gt; 0<br> 3 - 4 r &gt; 7<br> 13 &lt; 2 z + 3<br> 6 ≥ 9 - 0, 15 i
BartSMP [9]

Answer:

Part 1) u< 5.5  

Part 2) d > -80

Part 3) r < -1

Part 4) z>5

Part 5) i\geq 20

Step-by-step explanation:

<u><em>The question is</em></u>

Solve each inequality for the indicated variable

Part 1) we have

2u+12

subtract 12 both sides

2u< 23-12\\2u

Divide by 2 both sides

u< 5.5

The solution is the interval (-∞,5.5)

In a number line the solution is the shaded area at left of u=5.5 (open circle)

The number 5.5 is not included in the solution

Part 2) we have

0.1d+8 >0

subtract 8 both sides

0.1d > -8

Divide by 0.1 both sides

d > -80

The solution is the interval (-80,∞)

In a number line the solution is the shaded area at right of d=-80 (open circle)

The number -80 is not included in the solution

Part 3) we have

3-4r> 7

Subtract 3 both sides

-4r>7-3\\-4r>4

Divide by -4 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

r < -1

The solution is the interval (-∞,-1)

In a number line the solution is the shaded area at left of r=-1.1 (open circle)

The number -1.1 is not included in the solution

Part 4) we have

13< 2z+3

Subtract 3 both sides

13-3

Divide by 2 both sides

5

Rewrite

z>5

The solution is the interval (5,∞)

In a number line the solution is the shaded area at right of z=5 (open circle)

The number 5 is not included in the solution

Part 5) we have

6\geq 9-0.15i

Subtract 9 both sides

6-9\geq -0.15i\\-3\geq -0.15i

Divide by -0.15 both sides

Remember that, when you multiply or divide both sides of an inequality by a negative number, you must reverse the inequality symbol

20\leq i

Rewrite

i\geq 20

The solution is the interval [20,∞)

In a number line the solution is the shaded area at right of i=20 (closed circle)

The number 20 is included in the solution

6 0
3 years ago
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