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Valentin [98]
2 years ago
9

On the graph shown, what is f(-2)

Mathematics
1 answer:
WARRIOR [948]2 years ago
3 0

Answer:

3 because when x=2 the lines are at y 1 and 3, but the y 1 isn't shaded, so the answer is 3

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The arch beneath a bridge is​ semi-elliptical, a​ one-way roadway passes under the arch. The width of the roadway is 38 feet and
forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

\frac{x^2}{a^2}+\frac{y^2}{b^2}

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

a=\frac{38}{2}=19ft

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}

and we can simplify the equation, so we get:

\frac{x^2}{361}+\frac{y^2}{144}

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

\frac{y^{2}}{144}=1-\frac{x^{2}}{361}

y^{2}=144(1-\frac{x^{2}}{361})

we can add everything inside parenthesis so we get:

y^{2}=144(\frac{361-x^{2}}{361})

and take the square root on both sides, so we get:

y=\sqrt{144(\frac{361-x^{2}}{361})}

and we can simplify this so we get:

y=\frac{12}{19}\sqrt{361-x^{2}}

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

y=\frac{12}{19}\sqrt{361-(8)^{2}}

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0
3 years ago
Write a possible third degree polynomial with integer coefficient that have zeros: 1 2i, -4. Assume the leading coefficient to b
jasenka [17]

Answer:

The polynomial is:

p(x) = x^3 + 2x^2 - 3x + 20

Step-by-step explanation:

A third degree polynomial can be written in function of it's zeros x_1, x_2, x_3 the following way:

p(x) = a(x - x_1)(x - x_2)(x - x_3)

In which a is the leading coefficient.

Integer coefficient that have zeros: 1+2i, 1-2i, -4

Leading coefficient: 1

So

p(x) = 1(x - (1+2i))(x - (1-2i))(x - (-4))

p(x) = (x - 1 -2i)(x - 1 + 2i)(x + 4)

p(x) = ((x-1)^2 - (2i)^2)(x + 4)

p(x) = (x^2 - 2x + 1 - 4i^2)(x + 4)

Since i^2 = -1

p(x) = (x^2 - 2x + 1 + 4)(x + 4)

p(x) = (x^2 - 2x + 5)(x + 4)

p(x) = x^3 + 4x^2 - 2x^2 - 8x + 5x + 20

p(x) = x^3 + 2x^2 - 3x + 20

3 0
3 years ago
How man 2cm can fit in a 600mm by 500mm
Anna007 [38]
You can fit 15 2cm in a 600mm by 500mm.
3 0
3 years ago
Read 2 more answers
A cohort study was undertaken to examine the association between high lipid level and coronary heart disease. Participants were
Marrrta [24]

Step-by-step explanation:

1. Is a table which is contained in the attachment

2. The crude ratio measure

= 4000x3000+20*5800/7000*6000+200*3980

= 12000000+116000/42000000+796000

= 12116000/42796000

= 0.283

3. Stratum specific for high lipid

= 12000000/42000000

= 0.285

= 0.29

Stratum specific for chf

= 116000/796000

= 0.145

= 0.15

4. High lipid has higher risk than chd from the solution here

8 0
3 years ago
What equation Is correct ?
SpyIntel [72]
Hi there!

Let's first have a look at the basic goniometric statements, which say the following:
\sin( \alpha )  =  \frac{opposite \: side}{hypotenuse}  \\ \cos( \alpha )  =  \frac{adjecent \: side}{hyptenuse}

When we're looking from the point of view of angle G, we have the following data:
- The length of the opposite side is 15
- The length of the adjecent side is 8
- The length of the hypotenuse is 17

Now plug in this data into our general formulae.
\sin(g)  =  \frac{15}{17}  \\  \cos(g)  =  \frac{8}{17}

Hence, answer B. is correct.
~ Hope this helps you!
7 0
3 years ago
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