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Slav-nsk [51]
3 years ago
12

An aircraft is cruising at 720 km/h and covered 1000 km. How far would it travel in the same period of time is the speed increas

ed to 800 km/h
Mathematics
1 answer:
yanalaym [24]3 years ago
4 0

1000 km/h / 720 km/h = 1.39 hrs

800 km / hr * 1.39 hrs = 1112 km

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A bakery can make 640 bagels in 4 hours. How many can they bake in 16 hours.
lukranit [14]

Answer:

two ways

Step-by-step explanation:

there are two ways to do this

640/4 =160  

take 160x16 = 2,560

OR

640x4 = 2,560

4 because 4x4 = 16

5 0
2 years ago
Sonia walks to her aunt's house. She leaves home at 1025. She walks a total of 12km at an average speed of 5km/h. Work out the t
lisabon 2012 [21]

Answer: 1249 hrs

Step-by-step explanation:

Sophia walked for 12 km to get to her aunt's house.

She did this at a speed of 5km/h which means that the time taken was:

Time = Distance / Speed

= 12 / 5

= 2.4 hours

2.4 in hours:

= 0.4 * 60 minutes

= 24 minutes

= 2 hours 24 minutes

If she left at 1025, she would arrive at:

= 1025 + 2 hours 24

= 1249 hrs

3 0
3 years ago
Can someone help me with this math homework please!
andrew11 [14]

Answer:

I'm pretty sure it is 0.75

Step-by-step explanation:

It is a3 so that means it is the 3rd answer in the sequence.

6 0
3 years ago
Read 2 more answers
(1 point) Newton's law of cooling states that the temperature of an object changes at a rate proportional to the difference betw
slavikrds [6]

Answer:

a. \frac{dT}{dt}=k(T-Tm); T(0)=190

b. C_{0}=122

c. k=-0.00259

d. t=153.39838\\ minutos

Step-by-step explanation:

a. Newton's law of cooling states that the speed with which a body is cooled is proportional to the difference between its temperature and that of the medium in which it is found. Then, the initial value problem is given by:

Tm=68

\frac{dT}{dt}=k(T-Tm); T(0)=190

b. The differential equation obtained is a differential equation of separable variables:

\frac{dT}{T-Tm}=kdt\\\\\int {\frac{dT}{T-Tm}}=\int{kdt}\\\\Ln|T-Tm|=kt+C\\\\T(t)=C_{0}e^{kt}+Tm=C_{0}e^{kt}+68\\\\T(0)=C_{0}e^{k(0)}+68=190\\\\C_{0}=122

c. After 33 minutes of serving the coffee has cooled to 180°:

T(33)=122e^{33k}+68=180\\\\e^{33k}=\frac{112}{122}\\\\33k=Ln(\frac{112}{122})\\\\k=-0.00259

d.

150=122e^{-0.00259t}+68\\\\Ln(\frac{150-68}{122})=-0.00259t\\\\t=153.39838\\\\

8 0
3 years ago
What is the product?<br> (4y - 3)(2x(2)+ 3y-5)
aleksley [76]

Answer:

2 2

4y(2y +3y - 5) - 3(2y + 3y - 5)

3 2 2

=8y + 12y - 20y - 6y - 9y + 15

3 2

=8y + 6y - 29y + 15

Step-by-step explanation:

5 0
3 years ago
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