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Andrei [34K]
3 years ago
9

Find the value of the variables. 15 PTS!! {-12 -w^2} { 2k -81 } = {2f 3 } {-14 3 }

Mathematics
1 answer:
OLEGan [10]3 years ago
8 0
Why say fifteen points when it's only 5; people can see how much it's worth before even doing it.

Anyways, is there a plus in between the 2f 3 and between the -14 3?

If so, then w and k equal all real numbers and
f =   \frac{ - 1005}{22}  +  \frac{12}{11}k +  \frac{1}{11} {w}^{2} k  -  \frac{ 81}{22}  {w}^{2}
However if not, then I suggest downloading photo math and inserting it in the calculator itself to be exact.
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Use the distributive for dx(8+6)
kramer
That would be 14 then.
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It costs $60.00 to rent the gymnasium, plus $5.00 per person. What would be the total cost to rent the gymnasium for 40 people?
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5 0
2 years ago
I will mark as BRAINLIEST and 8 points if correct.
g100num [7]

Answer:

the answer is d

Step-by-step explanation:

6 0
2 years ago
Can someone pls help me with this ASAP!!!
VikaD [51]

Answer: D

The reason I say d is because the positive 3 is where the 9 is at on the y-axis

8 0
2 years ago
EXAMPLE 5 Evaluate the iterated integral 5 0 5 x sin(y2) dy dx. SOLUTION If we try to evaluate the integral as it stands, we are
Dimas [21]

\displaystyle\int_0^5\int_x^5\sin(y^2)\,\mathrm dy\,\mathrm dx

The integration region is the triangle in the x,y plane bounded by the lines y=5, y=x, and x=0. Reversing the order of integration, this is equal to

\displaystyle\int_0^5\int_0^y\sin(y^2)\,\mathrm dx\,\mathrm dy=\int_0^5y\sin(y^2)\,\mathrm dy

For the remaining integral, let u=y^2\implies\mathrm du=2y\,\mathrm dy:

\displaystyle\int_0^5y\sin(y^2)\,\mathrm dy=\frac12\int_0^{25}\sin u\,\mathrm du=-\frac12\cos u\bigg|_0^{25}=\frac{1-\cos(25)}2

6 0
3 years ago
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