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3 years ago

Which point is the centroid of the triangle?

Mathematics

1 answer:

Luda [366]3 years ago

7 0

Answer:

The answer is B) G

Step-by-step explanation:

G is at the center of the triangle. It is a centroid because it is where all the medians meet.

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Geometry question for homework.

mars1129 [50]

So remember that the distance formula is $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ .

$\sqrt{(4-4)^2+(-2-(-5))^2}\\ \sqrt{0^2+3^2}\\ \sqrt{0+9}\\ \sqrt{9}\\ 3$

Distance between (4,-5) and (4,-2) is 3 units.

$\sqrt{(1-(-1))^2+(1-4)^2}\\ \sqrt{2^2+(-3)^2}\\ \sqrt{4+9}\\ \sqrt{13}$

Distance between (1,1) and (-1,4) is √13 (or 3.61 rounded to the hundreths) units.

3 0

3 years ago

An equation in the form ax2+bx+c=0 is solved by the quadratic formula. The solution to the equation is shown below.x=−7±√ "572"

7nadin3 [17]

Answer:

B: a = 1, b= 7, c = -2

Explanation:

$\sf Quadratic \ Equation : \dfrac{-b\pm \sqrt{b^2 - 4ac} }{2a}$

Knowing This:

solve for b

-b = -7

b = 7

solve for a:

2a = 2

a = 1

solve c:

b² - 4ac = 57

7² - 4(1)(c) = 57

-4c = 57 - 49

-4c = 8

c = 8/-4 = -2

4 0

2 years ago

Read 2 more answers

Which equation represents a line parallel to the line shown on the graph? On a coordinate plane, a line goes through (negative 6

ELEN [110]

Answer:

$\boxed{ \mathrm{y = \ negative \ 3 x + 3}}$

Step-by-step explanation:

The coordinates are (-6,0) and (-8,6)

Finding slope of the line

Slope = $\frac{rise}{run} = \frac{y2-y1}{x2-x1}$

Slope = $\frac{6-0}{-8+6}$

Slope = $\frac{6}{-2}$

Slope = -3

Parallel lines have equal slopes.

So, the line which is parallel to this line is y = negative 3 x + 3

7 0

3 years ago

Read 2 more answers

The table lists how poverty level income cutoffs (in dollars) for a family of four have changed over time. Use the midpoint for

frez [133]

The poverty level cutoff in 1987 to the nearest dollar was $10787.

<h3>How to find a midpoint?</h3>

The midpoint as the point that divides the line segment exactly in half having two equal segments. Therefore, the midpoint presents the same distance between the endpoints for the line segment. The midpoint formula is: $\mathrm{Midpoint\:of\:}\left(x_1,\:y_1\right),\:\left(x_2,\:y_2\right):\quad \left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)$ .

For solving this exercise, first you need plot the points in a chart. See the image.

Your question asks to approximate the poverty level cutoff in 1987 to the nearest dollar using the midpoint formula. Note that the year 1987 is between 1980 and 1990, thus you should apply the midpoint formula from data for this year (1987).

$\mathrm{Midpoint\:of\:}\left(1980,8429),\:\left(1990,13145):\quad \left(\frac{1990+1980}{2},\:\:\frac{13145+8429}{2}\right)\\\\ \\$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\left(\frac{1990+1987}{2},\:\frac{13145+3843}{2}\right)\\ \\ =\left(\frac{3977}{2},\:\frac{21574}{2}\right)$

$\mathrm{Midpoint\:of\:}\left(1980,8429)\:=\=(\frac{3977}{2},10787)$

The answer for your question will be the value that you calculated for the y-coordinate. Then, the poverty level cutoff in 1987 to the nearest dollar was $10787.

Read more about the midpoint segment here:

brainly.com/question/11408596

7 0

2 years ago

3) Jackson ate a chocolate bar in 2 1/2 minutes. How much of the bar did he eat

nignag [31]

Answer:

0.4 of the chocolate bar.

Step-by-step explanation:

3 0

2 years ago