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3 years ago

PLEASE HELP ME I DO NOT HAVE MUCH TIME

Mathematics

1 answer:

marshall27 [118]3 years ago

5 0

Answer:

Step-by-step explanation:

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2.67

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So Naomi Brough Five bags of chips but theirs three people she's sharing with How many does each Person get.Divide.

sladkih [1.3K]

Each person would get 1 2/3 bags of chips.

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Given f(x) = x ^ 2 - 6x + 8 and g(x) = x + 2 solve f(x) = g(x) . Use the tables below to help you, but please explain how you ca

Travka [436]

Answer:

see explanation

Step-by-step explanation:

Given

f(x) = x² - 6x + 8 and g(x) = x + 2

To solve f(x) = g(x), equate the right sides, that is

x² - 6x + 8 = x + 2 ← subtract x + 2 from both sides

x² - 7x + 6 = 0 ← in standard form

(x - 1)(x - 6) = 0 ← in factored form

Equate each factor to zero and solve for x

x - 1 = 0 ⇒ x = 1

x - 6 = 0 ⇒ x = 6

These solutions can be verified from the tables, that is

f(x) = g(x) = 3 ← when x = 1

f(x) = g(x) = 8 ← when x = 6

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4 years ago

What is the factored form of 8x²-36x-20?

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Step-by-step explanation:

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3 years ago

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1. S(–4, –4), P(4, –2), A(6, 6) and Z(–2, 4) a) Apply the distance formula for each side to determine whether SPAZ is equilatera

Aleksandr [31]

Answer:

a) SPAZ is equilateral.

b) Diagonals SA and PZ are perpendicular to each other.

c) Diagonals SA and PZ bisect each other.

Step-by-step explanation:

At first we form the triangle with the help of a graphing tool and whose result is attached below. It seems to be a paralellogram.

a) If figure is equilateral, then SP = PA = AZ = ZS:

$SP = \sqrt{[4-(-4)]^{2}+[(-2)-(-4)]^{2}}$

$SP \approx 8.246$

$PA = \sqrt{(6-4)^{2}+[6-(-2)]^{2}}$

$PA \approx 8.246$

$AZ =\sqrt{(-2-6)^{2}+(4-6)^{2}}$

$AZ \approx 8.246$

$ZS = \sqrt{[-4-(-2)]^{2}+(-4-4)^{2}}$

$ZS \approx 8.246$

Therefore, SPAZ is equilateral.

b) We use the slope formula to determine the inclination of diagonals SA and PZ:

$m_{SA} = \frac{6-(-4)}{6-(-4)}$

$m_{SA} = 1$

$m_{PZ} = \frac{4-(-2)}{-2-4}$

$m_{PZ} = -1$

Since $m_{SA}\cdot m_{PZ} = -1$ , diagonals SA and PZ are perpendicular to each other.

c) The diagonals bisect each other if and only if both have the same midpoint. Now we proceed to determine the midpoints of each diagonal:

$M_{SA} = \frac{1}{2}\cdot S(x,y) + \frac{1}{2}\cdot A(x,y)$

$M_{SA} = \frac{1}{2}\cdot (-4,-4)+\frac{1}{2}\cdot (6,6)$

$M_{SA} = (-2,-2)+(3,3)$

$M_{SA} = (1,1)$

$M_{PZ} = \frac{1}{2}\cdot P(x,y) + \frac{1}{2}\cdot Z(x,y)$

$M_{PZ} = \frac{1}{2}\cdot (4,-2)+\frac{1}{2}\cdot (-2,4)$

$M_{PZ} = (2,-1)+(-1,2)$

$M_{PZ} = (1,1)$

Then, the diagonals SA and PZ bisect each other.

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3 years ago