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Minchanka [31]
4 years ago
8

Given: x - 5 > -10.

Mathematics
1 answer:
Elan Coil [88]4 years ago
4 0
<span>The solution to the problem is as follows:

</span><span>x - 5 > -10
</span>
is equivalent to : 

x - 5 + 5 > -10 + 5
 
x  >  5
 
therefore, 

{x | x ∈ R, x < 5}  <span><---- answer 

I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!


</span>
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The answer is 7,323 al you have to do is pay atention
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Quadrilateral RSTU is a parallelogram. What must be the value of x?
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I set x-3 and 3x-13 equal to each other and then got x equal to 5. So, I believe the correct answer would be C.) 5
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Given: sin ∅= 4/5 and cos x = -5/13 ; evaluate the following expression.<br><br> tan( ∅ - x )
Pavlova-9 [17]

By definition of tangent,

tan(θ - x) = sin(θ - x) / cos(θ - x)

Expand the sine and cosine terms using the angle sum identities,

sin(x ± y) = sin(x) cos(y) ± cos(x) sin(y)

cos(x ± y) = cos(x) cos(y) ∓ sin(x) sin(y)

from which we get

tan(θ - x) = (sin(θ) cos(x) - cos(θ) sin(x)) / (cos(θ) cos(x) + sin(θ) sin(x))

Also recall the Pythagorean identity,

cos²(x) + sin²(x) = 1

from which we have two possible values for each of cos(θ) and sin(x):

cos(θ) = ± √(1 - sin²(θ)) = ± 3/5

sin(x) = ± √(1 - cos²(x)) = ± 12/13

Since there are 2 choices each for cos(θ) and sin(x), we'll have 4 possible values of tan(θ - x) :

• cos(θ) = 3/5, sin(x) = 12/13 :

tan(θ - x) = -56/33

• cos(θ) = -3/5, sin(x) = 12/13 :

tan(θ - x) = 16/63

• cos(θ) = 3/5, sin(x) = -12/13 :

tan(θ - x) = -16/63

• cos(θ) = -3/5, sin(x) = -12/13 :

tan(θ - x) = 56/33

7 0
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1) You are designing a new kiddie soccer arena. The area of the rectangular
nikdorinn [45]

Answer:

The length of the rectangular field is 12 ft and the width is 5 ft.

Step-by-step explanation:

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\text{Area} = \text{length}\times \text{width}

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The length of the field is:

l = w + 7

Compute the width of the field as follows:

\text{Area} = \text{length}\times \text{width}

60=(w+7)\times w\\\\60=w^{2}+7w\\\\w^{2}+7w-60=0\\

Factorize the last equation by splitting the middle term as follows:

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Now, since the width of rectangular field cannot be negative, the width is 5 ft.

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l = w + 7

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The length of the rectangular field is 12 ft.

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The focus of the parabola -40x = y2 is:<br><br> (-10, 0)<br> (0, -10)<br> (0, 10)<br> (10, 0)
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Answer:

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The given equation of the parabola is in the form of y^2=4ax where the focus is located at (a,0). Therefore, the focus of the parabola is (-10,0).

3 0
2 years ago
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