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mel-nik [20]
3 years ago
4

A coordinate plane with a line drawn passing through the points (0, 3) and (1,1). Which equation represents the graphed function

? y = –2x + 3 y = 2x + 3 y = x + 3 y = –x + 3
Mathematics
1 answer:
aliina [53]3 years ago
7 0

Answer: A.) y = -2x + 3 because 0 is x and 3 is y for the first answer so -2(0) + 3 is 0 + 3 and that is 3 and for the second answer 1 is both x and y so -2(1) + 3 is -2 + 3 and the answer for this is 1 so the answer is A.

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(X - 5) (x + 5)

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Use the grouping method to factor x3 + x2 + 5x + 5.
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Answer:

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Answer:-13,-25

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BlackZzzverrR [31]

Answer:

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Step-by-step explanation:

7 0
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Read 2 more answers
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IgorLugansk [536]

Answer :

Option B

Step by step explanation :

As we can see in figure, Triangle is right angled at A

In ∆ABC

By Pythagoras theorem,

BC² = AC² + AB²

=> BC² = (3)² + (4)²

=> BC² = 9 + 16

=> BC² = 25

=> BC = 5 cm

We know,

\:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2}\: x\: base\: x\: height}

Here,

base = AC = 3cm

height = AB = 4cm

=> \:\mathsf{Area \:of\: triangle}=\:\mathsf{\frac{1}{2} \:x\: 3cm\: x\:4cm}

=> \:\mathsf{Area \:of\: triangle\: = \:3cm\: x\: 2cm}

=> \:\bf\boxed{Area \:of\: triangle\: = \:6cm²}

As BC = DE

And then BD = EC

it shows the property of rectangle

So BD = 6 cm

Now,

\:\mathsf{Area \:of\: rectangle\: =\: length \:x\: width}

=> Area of rectangle = 6cm x 5cm

=> \:\bf\boxed{Area\: of\: rectangle\: = \:30cm²}

Now,

Area of the figure = Area of rectangle + Area of triangle

=> Area of the figure = 30cm² + 6cm²

=> \:\bf\boxed{Area\: of\: the\: figure\: = \:36cm²}

Therefore, <u>option B</u> is the correct answer for this question.

3 0
3 years ago
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