Answer:
C po ang Alam kong sagot
Step-by-step explanation:
it's look like a test
Answer:
The maximum amount of money the chemistry club can spend without going over their buget is $81.4 ... With a total of 6 hours their allowed to use the room for.
Step-by-step explanation:
$49 is our constant and will not change. 5.40 however will. Let's use variable h for the amount hours they can rent the room for. Now we can make an inequality;
49+ 5.40h < 86.80
5.40h < 86.80
5.4h< 37.8
h< 7
Now that we know h will have to be less than seven for the chemistry club to spend less than their buget we can find that 6 is the maxium amount of hours they can spend in the room while staying within their budget.
(This answer does not consider decimals or half hours)
Answer:
Each bag originally had 35 pieces of candy
Step-by-step explanation:
Since the bags are identical, Let them Number of candies in each bag sue had be x. Thus, she had 5x candies. Since she lost 25 pieces, then she now has;
5x - 25 candies left.
We are told that Ted had 4 bags with the same number of candies like Sue had. Thus, he has 4x candies.
He mysteriously found 10 additional pieces. Total Ted now has is;. 4x + 10
Finally, we are told that Sue and Ted now have an equal number of candies.
Thus;
5x - 25 = 4x + 10
Rearranging, we have;
5x - 4x = 25 + 10
x = 35
Thus, each bag originally had 35 pieces of candy
