Answer:
f(x) = x² - 10x + 24
Step-by-step explanation:
The quadratic function has a graph that passes through the points (4,0) and (6,0).
Therefore, the graph has two x-intercepts at x = 4 and x = 6 and those are the roots of the equation.
So, (x - 4) and (x - 6) are two factors of the quadratic equation.
Then we can write the equation as
f(x) = (x - 4)(x - 6)
⇒ f(x) = x² - 4x - 6x + 24
⇒ f(x) = x² - 10x + 24
Hence, this is the required quadratic function in standard form. (Answer)
Answer:
answer D or the 4th answer
Gotcha.
We know Sean spent 15 more minutes than Faith.
So, we know this to be true:
Sean = 15 + Faith
We also know that Sean and Faith spent a TOTAL time of 55 minutes on homework.
So, we have this:
Sean + Faith = 55
We can solve for Faith's time spent in homework now since we have two equations.
Here are the two equations we have:
Sean = 15 + Faith
Sean + Faith = 55
To make solving for Faith easier, I'm going to rearrange the second equation to this:
55 = Sean + Faith
Now, we solve the problem.
Sean = 15 + Faith
55 = Sean + Faith
We know what Sean is, he is 15 + Faith.
So, we can plug in 15 + Faith into Sean in the second equation.
55 = 15 + Faith + Faith
Simplify:
55 = 15 + 2Faith
55 - 15 = 15 - 15 + 2Faith
(I subtracted 15 from both sides)
40 = 2Faith
Now, divide by 2 on both sides to get Faith's time.
40 ÷ 2 = 2Faith ÷ 2
20 = Faith
If you have any questions or comments then please post them. Otherwise, good luck, and I hope this was useful!
<span>Since Sturge's Rule states that the optimal number of bins is equal to the 1 plus 3.3 log(n), where n is the number of data points, the estimated solution (since you can only have whole bins) is to provide 6 bins, each storing 42 to 43 data points.</span>
ANSWER :
The answer is :
EXPLANATION :
Note that cotangent is only positive when the angle is in the first or third quadrant.
Since y is not in the first quadrant, it must be in the third quadrant.
So the x and y are both negative.
An angle with a terminal point (x, y)
The cotangent is x/y
We can equate :
Since x and y are both negatives, x = -9 and y = -13
We can have the triangle :
The hypotenuse will be :
We are asked to find the value of sec y.
In an angle with a terminal point (x, y)
The secant is :
The hypotenuse is 5√10 and x = -9
The value of sec will be :