Answer:
It's an internal joke to say the language is basically C with some extra stuff (like classes)
the "++" is short for
C += 1 or
C = C + 1 which is a common calculation among programmers so they named it C++ to be a more commercial and attractive name than "C with classes"
Explanation:
Answer:
see explaination
Explanation:
import random
def number_guess(num):
n = random.randint(1, 100)
if num < n:
print(num, "is too low. Random number was " + str(n) + ".")
elif num > n:
print(num, "is too high. Random number was " + str(n) + ".")
else:
print(num, "is correct!")
if __name__ == '__main__':
# Use the seed 900 to get the same pseudo random numbers every time
random.seed(900)
# Convert the string tokens into integers
user_input = input()
tokens = user_input.split()
for token in tokens:
num = int(token)
number_guess(num)
Decrease. Think like this, if you were standing in the ocean getting hit by waves, frequency would be how many waves hit you in a certain amount of time. If there were lots of little waves hitting you the number of waves (the frequency) would be high, whereas big waves are slower and take more time to reach you so you would get hit by less of them in the same time frame. The less frequent, the longer the wave.
Answer:
- <u>1,000W</u> (rounded to one significant figure)
Explanation:
I will answer in English.
The question is:
- <em>What is the power of a filament lamp that connects to the 220 V network, knowing that it has a resistance of 50 ohms?</em>
<em />
<h2>Solution</h2>
<em />
<em>Power</em>, <em>voltage</em>, <em>resistance</em>, and current, are related by either of the following equations:
Where:
- R is resistance in ohms (Ω)
- V is voltage in volts (V), and
- I is current in amperes (A)
Since you know the voltage (<em>220V</em>) and the resistance (<em>50Ω</em>), you can use the last equation:
Since the magnitude 50Ω has one significant figure, your answer should be rounded to one significant figure. That is <u>1,000W.</u>
