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alexandr402 [8]

3 years ago

8

What is 15% of $12.75.

1 answer:

USPshnik [31]3 years ago

5 0

$\frac{15}{100}=0.15 \\ \\ 0.15*12.75=1.91$

$1.91

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Kayla says that the point labeled C in the diagram below is the center. Raymond says that point C is the radius. A sphere. The c

liq [111]

Answer:

Kayla is correct; the center is a fixed point in the middle of the sphere.

Step-by-step explanation:

Kayla is correct. Raymond is wrong because a point cannot be a radius: a radius is a line segment from the center to the surface.

The center is the fixed point in the middle of the sphere.

6 0

3 years ago

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How many quarters are thee in 4 1/2

Neko [114]

Hi there!

quarter:18

<u><em>1.Find common denominator in 4 and 1/2:</em></u>

<u><em /></u> $4=\frac{1}{4}$ <u><em /></u>

<u><em /></u> $\frac{1}{2}=\frac{2}{4}$ <u><em /></u>

<u><em>2.Convert 4 2/4 into mixed number:</em></u>

<u><em /></u> $4\frac{2}{4}=\frac{18}{4}$ <u><em /></u>

<u><em>3.Divide 18/4 by 1/4:</em></u>

<u><em /></u> $\frac{18}{4}*\frac{1}{4}=18$ <u><em /></u>

Therefore, there is 18 quarters in 4 1/2.

4 0

3 years ago

What is 2x + 11y when x = 4 and y = 2?<br><br> A. 30<br><br> B. 38<br><br> C. 48<br><br> D. 136

Alla [95]

The correct answer is A

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3 years ago

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The probability that Leon makes a three-point shot in basketball is 15%. For practice, Leon will regularly

mr_godi [17]

.07Step-by-step explanation:

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3 0

3 years ago

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Could someone help me, please?

k0ka [10]

We can rewrite the expression under the radical as

$\dfrac{81}{16}a^8b^{12}c^{16}=\left(\dfrac32a^2b^3c^4\right)^4$

then taking the fourth root, we get

$\sqrt[4]{\left(\dfrac32a^2b^3c^4\right)^4}=\left|\dfrac32a^2b^3c^4\right|$

Why the absolute value? It's for the same reason that

$\sqrt{x^2}=|x|$

since both $(-x)^2$ and $x^2$ return the same number $x^2$ , and $|x|$ captures both possibilities. From here, we have

$\left|\dfrac32a^2b^3c^4\right|=\left|\dfrac32\right|\left|a^2\right|\left|b^3\right|\left|c^4\right|$

The absolute values disappear on all but the $b$ term because all of $\dfrac32$ , $a^2$ and $c^4$ are positive, while $b^3$ could potentially be negative. So we end up with

$\dfrac32a^2\left|b^3\right|c^4=\dfrac32a^2|b|^3c^4$

3 0

3 years ago