Answer:
Step-by-step explanation:
We have been given that Wren’s first display box is 6 inches long, 9 inches wide, and 4 inches high. We are asked to find the volume of display box.
We know that the box is in form of cuboid, so its volume would be length times width times height.
![\text{Volume of display box}=6\text{ in}\times 9\text{ in}\times 4\text{ in}](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20display%20box%7D%3D6%5Ctext%7B%20in%7D%5Ctimes%209%5Ctext%7B%20in%7D%5Ctimes%204%5Ctext%7B%20in%7D)
![\text{Volume of display box}=216\text{ in}^3](https://tex.z-dn.net/?f=%5Ctext%7BVolume%20of%20display%20box%7D%3D216%5Ctext%7B%20in%7D%5E3)
Therefore, the volume of the display box is 216 cubic inches.
Answer:
The answers would be as follows:
1. d
2. a
3. a
Step-by-step explanation:
To find the combined terms, focus only on the terms that have the same variable value. See the examples below.
1.
7 + 19t - 6t
7 + (19t - 6t)
7 + 13t
2.
5/6x - 2/3x
(5/6x - 2/3x)
1/6x
3.
8 + 16r - 9r
8 + (16r - 9r)
8 + 7r
Answer:
4 grams
Step-by-step explanation:
Mass is conserved, so if you start with 4 grams, you end with 4 grams.
Answer:
The correct answer to the following question will be "384".
Step-by-step explanation:
We are having,
![P(-0.05](https://tex.z-dn.net/?f=P%28-0.05%3Cp-p%3C0.05%29%3D0.95)
On solving, we get
⇒ ![P(\frac{-0.05}{\sqrt{\frac{pq}{n}}}](https://tex.z-dn.net/?f=P%28%5Cfrac%7B-0.05%7D%7B%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%7D%7D%3CZ%3C%5Cfrac%7B-0.05%7D%7B%5Csqrt%7B%5Cfrac%7Bpq%7D%7Bn%7D%7D%7D%3D0.95%29)
⇒ ![\frac{0.05}{\sqrt{\frac{p(1-p)}{n}}} =1.96](https://tex.z-dn.net/?f=%5Cfrac%7B0.05%7D%7B%5Csqrt%7B%5Cfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%20%3D1.96)
On applying cross-multiplication, we get
⇒ ![0.05^2=1.96^2\times \frac{P(1-p)}{n}](https://tex.z-dn.net/?f=0.05%5E2%3D1.96%5E2%5Ctimes%20%5Cfrac%7BP%281-p%29%7D%7Bn%7D)
⇒ ![0.05^2n=1.96^2-1.96^2p^2](https://tex.z-dn.net/?f=0.05%5E2n%3D1.96%5E2-1.96%5E2p%5E2)
⇒
...(equation 1)
When "p" seems to be the population proportion, (equation 1) approach, which is special
∴ ![b^2-4ac=0](https://tex.z-dn.net/?f=b%5E2-4ac%3D0)
On putting the values in the above expression, we get
⇒ ![(1.96)^4-4\times 0.05^2\times 1.96^2n=0](https://tex.z-dn.net/?f=%281.96%29%5E4-4%5Ctimes%200.05%5E2%5Ctimes%201.96%5E2n%3D0)
⇒ ![1.98^2-4\times 0.05^2n=0](https://tex.z-dn.net/?f=1.98%5E2-4%5Ctimes%200.05%5E2n%3D0)
⇒ ![n=\frac{1.96^2}{4\times 0.05^2}](https://tex.z-dn.net/?f=n%3D%5Cfrac%7B1.96%5E2%7D%7B4%5Ctimes%200.05%5E2%7D)
⇒ ![n=384.16=384](https://tex.z-dn.net/?f=n%3D384.16%3D384)
When you divide by a fraction you are multiplying by the reciprocal (turn it up side down) of the fraction so...
12 times 5/6 = 72/5