Slope intercept form of a line perpendicular to 3x + y = -8, and passing through (-3,1) is 
<u>Solution:</u>
Need to write equation of line perpendicular to 3x+y = -8 and passes through the point (-3,1).
Generic slope intercept form of a line is given by y = mx + c
where m = slope of the line.
Let's first find slope intercept form of 3x + y = -8
3x + y = -8
=> y = -3x - 8
On comparing above slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line 3x + y = -8 , slope m = -3
And as the line passing through (-3,1) and is perpendicular to 3x + y = -8, product of slopes of two line will be -1 as lies are perpendicular.
Let required slope = x

So we need to find the equation of a line whose slope is
and passing through (-3,1)
Equation of line passing through
and having lope of m is given by


Substituting the values we get,

Hence the required equation of line is found using slope intercept form
Answer:
284cm^2
Step-by-step explanation:
first, we split up the shape into seperate sections that we can easily find the areas of.
i will draw vertical lines in the bottom left and right, leaving me with 2 seperate rectangles and 1 irregular pentagon.
we know that these rectangles are 4x8cm, so we do 4 * 8 which gives us 32.
there are 2 of these, so 32 x 2 = 64cm^2.
now, i chose to seperarte the pentagon into a rectangle and a triangle,
and i found the height and width of the rectangle to be (18 - (4+4)) x (8+7), or 10 x 15.
the area of the rectangle is 150cm^2.
now, for the triangle.
the line through the centre of th shape is 22cm long, but we only want the part in the triangle. luckily, there are mesurements that can help us with this.
8 + 7 = 15.
22 - 15 = 7.
now we know that the height of the triangle is 7 cm.
from earlier, we also know the base, which is 10cm.
7 x 10 = 70cm^2.
now we add all these together:
70 + 150 + 64 = 284cm^2
Answer:
hmmm interesting
Step-by-step explanation:
Answer:
true
Step-by-step explanation:
your their child.