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3 years ago

How do i solve y+4=4/3(x+1)

Mathematics

1 answer:

ICE Princess25 [194]3 years ago

5 0

Y + 4 = 4/3(x + 1)...first we distribute
y + 4 = 4/3x + 4/3 ...now we subtract 4 from both sides
y = 4/3x + 4/3 - 4
y = 4/3x + 4/3 - 12/3
y = 4/3x - 8/3 <======
u will have a slope of 4/3....and a y int of (0,-8/3)...ur x int is (2,0)

in standard form, it is :
y = 4/3x - 8/3
-4/3x + y = -8/3
4x - 3y = 8....in case u need to find some points to graph

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What is f(5) if f(1) = 3. 2 and f(x 1) = Five-halves(f(x))?

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Function assign value from one set to another. The value of f(5), if f(1) = 3.2 and f(x+1) = Five-halves(f(x)) is 125.

<h3>What is Function?</h3>

A function assigns the value of each element of one set to the other specific element of another set.

As it is given the value of the function f(1) is 3.2, while the value of f(x+1) is $f(x+1) = \dfrac{5}{2}[f(x)]$ , therefore, in order to find the value of f(5), we need to calculate the value of f(4).

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f(4)

$f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(4)=f(3+1) = \dfrac{5}{2}[f(3)]\\\\f(4) = 2.5 \times 20\\\\f(4) = 50$

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$f(x+1) = \dfrac{5}{2}[f(x)]\\\\f(5)=f(4+1) = \dfrac{5}{2}[f(4)]\\\\f(5) = 2.5 \times 50\\\\f(5) = 125$

Hence, the value of f(5), if f(1) = 3. 2 and f(x+1) = Five-halves(f(x)) is 125.

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