Answer:
A(n)=130+13(n-1) ; 86
Step-by-step explanation:
Here is the sequence
130,143,156,169.......
the first term denoted by a is 130 and the common difference denoted by d is second term minus first term
143 - 130 = 13
Hence a=130 and d = 13
Now we have to evaluate to 13th term.
The formula for nth term of any Arithmetic Sequence is
A(n) = a+(n-1)d
Hence substituting the values of a ,and d get
A(n)=130+13(n-1)
To find the 13th term , put n = 13
A(13)=130+13*(13-1)
= 130+13*12
= 130+156
A(13) = 286
Answer: -2
Step-by-step explanation: add the -8 to both sides to get X by itself
-10 + 8 = -2
Answer:
x=25
x=47
y=25 x=10
y=20
Step-by-step explanation:
2x+10=60
-10 -10
2x=50
2x/2=50/2
x=25
2x+6=100
-6 -6
2x=94
2x/2=94/2
x=47
5y-25=100
+25 +25
5y=125
5y/5=125/5
y=25
11x-30+100=180
11x+70=180
-70 -70
11x=110
11x/11=110/11
x=10
7y-10=3y+70
+10 +10
7y=3y+80
-3y-3y
4y=80
4y/4=80/4
y=20
hopefully this helps :)
I could help. So mark days as the X value and hours as the Y value
so for the days(x) start with 1 and put in the hours(y) 24 the for the second column in the days(x) box put 2 and in the hours(y) put 48 then continue to at 12 to the hours(y) and 1 to the days(x)
