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ioda
3 years ago
10

Exponential form of 1000000

Mathematics
2 answers:
aalyn [17]3 years ago
7 0

There are two ways on how to write 1,000,000 into an exponential form, which are either 10^6 or 1.0 x 10^6.

Hope this helped!

Nate

bulgar [2K]3 years ago
4 0
1.0 x 10^6 the answer to the question
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your order 4 fish tacos and a hamburger. The cost of the hamburger is $2.50. Your total bill before tax is $14.30. Write and sol
ValentinkaMS [17]

Answer:

$2.95

Step-by-step explanation:

Step 1:

( $14.30 - $2.50 ) ÷ 4

Step 2:

$11.80 ÷ 4

Answer:

$2.95

Hope This Helps :)

4 0
3 years ago
Read 2 more answers
Look at the picture to see the question.
Andru [333]

Answer:

y = 5/7x + 5

Step-by-step explanation:

If you replace the x and y in the equation with points x and y of point (35, 30) and change the 10 to b you can solve for b which is the what changes from the original equation to this one.

30 = 5/7(35) + b

30 = 25 + b

5 = b

Since the equations are parallel they have the same slope.

This is the equation for a parallel line that passes through point (35, 30):

y = 5/7x + 5

Hope this made sense! Please give Brainliest!

6 0
2 years ago
Write a real world situation that could be represented by x+20>50
Korolek [52]

Answer:

will have a trillionare by that time

Step-by-step explanation:

3 0
3 years ago
I need help pllllllease help me
MissTica
Im sorry i dont understand the question.. Is there another form of the question you can give me?
7 0
3 years ago
State how many imaginary and real zeros the function has.
alukav5142 [94]

Answer:

B. 4 imaginary; 1 real

Step-by-step explanation:

Given the polynomial:

x^5 + 7*x^4 + 2*x^3 + 14*x^2 + x + 7

it can be reordered as follows

(x^5 + 2*x^3 + x ) + (7*x^4  + 14*x^2 + 7)

Taking greatest common factor at each parenthesis

x*(x^4 + 2*x^2 + 1) + 7*(x^4  + 2*x^2 + 1)

Taking again the greatest common factor

(x + 7)*(x^4 + 2*x^2 + 1)

Replacing x^2 = y in the second parenthesis

(x + 7)*(y^2 + 2*y + 1)

(x + 7)*(y + 1)^2

Coming back to x variable

(x + 7)*(x^2 + 1)^2

There are two options to find the roots

(x + 7) = 0

or

(x^2 + 1)^2 = 0 which is the same that (x^2 + 1) = 0

In the former case, x = -7 is the real root.  In the latter, (x^2 + 1) = 0 has no real solution. Therefore, there is only 1 real root in the polynomial.

8 0
3 years ago
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