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3 years ago

Coral bleaching can be hazardous to some fish species because coral reefs provide unique habitats for fish

Mathematics

1 answer:

lana66690 [7]3 years ago

5 0

Answer:

A) coral reefs provide unique habitats for fish

Step-by-step explanation:

Coral bleaching can be hazardous to some fish species because

A) coral reefs provide unique habitats for fish

B) decomposition of corals can lead to ocean acidification

C) the dead corals attract predators that feed on the fish

D) the corals are the primary source of O2O2 in ocean water

Solution:

Coral bleaching is process in which corals are stressed as a result of changes temperature, light, or nutrients causing them to turn completely white. Coral reefs are is a very diverse ecosystems with ecological and economic value.

Coral reefs are a very important habitat for the fishes providing home to about 25% of fishes. The coral reefs are used for shelter during the day, and as a hunting ground by night.

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PLEASE HELP Provide 3 examples of how Franklin Delano Roosevelt changed the course of history 5-8 sentences PLEASE SOMEONE WHO W

Vesna [10]

Well, there are a lot of ways in which President Roosevelt impacted the US. He brought a nation to the brink of disaster from the Great depression and helped overcome it with his New deal which gave a lot of people jobs and helped rebuild America because of the CCC, among other programs in the New Deal. He also guided America through World War 2 and created peace between nations by signing the Atlantic Charter which then was the basis for the United Nations. As you can see President Roosevelt did alot to help America, he was a very good president

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3 years ago

Use the formula d = ( r − c ) t to find c if d = 6 , r = 4 , and t = 2 . c=

Minchanka [31]

First, we are going to want to plug in the values we are given. In this case, we will end up with the equation:

$6 = (4 - c) 2$

From here, we can solve the equation to find $c$ :

$6 = 2(4 - c)$

Apply the commutative property to rearrange the terms on the right-side of the equation to make the distributive property more apparent

$6 = 8 -2c$

Apply the distributive property

$-2 = -2c$

Subtract 8 from both sides of the equation

$1 = c$

Divide both sides of the equation by -2

We have found that c = 1.

7 0

3 years ago

5.65 times 3.4 estimate

lidiya [134]

We can round 5.65 up to 6 and 3.4 down to 3.
3 * 6 = 18
now let's see how close our estimate is to the real answer
5.65 * 3.4 = 19.21
Our answer was pretty close to the real answer!

Hope I helped!
~ Zoe

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4 years ago

Read 2 more answers

At Western University the historical mean of scholarship examination scores for freshman applications is 900. A historical popul

vampirchik [111]

Answer:

a) Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b) The 95% confidence interval would be given by (910.05;959.95)

c) Since we confidence interval not ocntains the value of 900 we fail to reject the null hypothesis that the true mean is 900.

d) $z=\frac{935 -900}{\frac{180}{\sqrt{200}}}=2.750$

Since is a bilateral test the p value is given by:

$p_v =2*P(Z>2.750)=0.0059$

Step-by-step explanation:

a. State the hypotheses.

On this case we want to check the following system of hypothesis:

Null Hypothesis: $\mu =900$

Alternative hypothesis: $\mu \neq 900$

b. What is the 95% confidence interval estimate of the population mean examination score if a sample of 200 applications provided a sample mean x¯¯¯= 935?

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=935$ represent the sample mean for the sample

$\mu$ population mean (variable of interest)

$\sigma=180$ represent the population standard deviation

n=200 represent the sample size

The confidence interval for the mean is given by the following formula:

$\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=3278.222$

The sample deviation calculated $s=97.054$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that $z_{\alpha/2}=1.96$