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saul85 [17]
3 years ago
13

Coral bleaching can be hazardous to some fish species because coral reefs provide unique habitats for fish

Mathematics
1 answer:
lana66690 [7]3 years ago
5 0

Answer:

A) coral reefs provide unique habitats for fish

Step-by-step explanation:

Coral bleaching can be hazardous to some fish species because

A) coral reefs provide unique habitats for fish

B) decomposition of corals can lead to ocean acidification

C) the dead corals attract predators that feed on the fish

D) the corals are the primary source of O2O2 in ocean water

Solution:

Coral bleaching is process in which corals are stressed as a result of changes temperature, light, or nutrients causing them to turn completely white. Coral reefs are is a very diverse ecosystems with ecological and economic value.

Coral reefs are a very important habitat for the fishes providing home to about 25% of fishes. The coral reefs are used for shelter during the day, and as a hunting ground by night.

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When comparing the graphs of y = x and y > x, what is a difference in the graphs?
mars1129 [50]
I donnt think that there is a solution, but could be wrong
8 0
3 years ago
5) If Oskar bisects the diameter of a circle, what is he trying to construct?
pav-90 [236]

Answer:

Center = (5,-3) and radius = 7

Step-by-step explanation:

(5) If Oskar bisects the diameter of a circle, what is he trying to construct the radius of the circle.

(6) The given equation is :

(x-5)^2+(y+3)^2=49

The general equation of circle is given by :

(x-a)^2+(y-b)^2=r^2 ...(1)

Where

(a,b) are the coordinates of the centre and r is the radius.

The given equation can be written as :

(x-5)^2+(y+3)^2=7^2 ..(2)

Comparing equation (1) and (2) we get :

a = 5, b = -3 and r = 7

So,

Center = (5,-3) and radius = 7

Hence, this is the required solution.

8 0
3 years ago
Recall the scenario about Eric's weekly wages in the lesson practice section. Eric's boss have been very impressed with his work
Solnce55 [7]

Answer:  

1)\quad f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) D: x = [0, 24]

3) R: y = [0, 384]

4) see graph

<u>Step-by-step explanation:</u>

Eric's regular wage is $12 per hour for all hours less than 9 hours.

The minimum number of hours Eric can work each day is 0.

f(x) = 12x    for   0 ≤ x < 9

Eric's overtime wage is $18 per hour for 9 hours and greater.

The maximum number of hours Eric can work each day is 24 (because there are only 24 hours in a day).

f(x) = 18(x - 8) + 12(8)

    = 18x - 144 + 96

    = 18x - 48           for 9 ≤ x ≤ 24

The daily wage where x represents the number of hours worked can be displayed in function format as follows:

f(x)=\bigg\{\begin{array}{ll}12x&0\leq x

2) Domain represents the x-values (number of hours Eric can work).

The minimum hours he can work in one day is 0 and the maximum he can work in one day is 24.

D:  0 ≤ x ≤ 24        →        D: x = [0, 24]

3) Range represents the y-values (wage Eric will earn).

Eric's wage depends on the number of hours he works. Use the Domain (given above) to find the wage.

The minimum hours he can work in one day is 0.

f(x) = 12x

f(0) = 12(0)

     =  0

The maximum hours he can work in one day is 24 <em>(although unlikely, it is theoretically possible).</em>

f(x) = 18x - 48

f(24) = 18(24) - 48

       = 432 - 48

       = 384

D:  0 ≤ y ≤ 384        →        D: x = [0, 384]

4) see graph.

Notice that there is an open dot at x = 9 for f(x) = 12x

and a closed dot at x = 9 for f(x) = 18x - 48

6 0
3 years ago
Find the interquartile range of the data.
likoan [24]

The answer is 14. Here is how I work it out.


First we are going have to identify quartile 1 and quartile 3.


So after putting the numbers in order from least to greatest mark the number with a half way point.

This is optional but it will help us spot the sections better.


31,33,35,41,43,|46,48,49,49,50

Next put parentheses around the remaining groups of numbers.

(31,33,35,41,43,)|(46,48,49,49,50)


For the next step we have to find the median of each group.


(31,33,35,41,43,)|(46,48,49,49,50)


The median of each group, are called the quartiles, the median of the lower half is quartile 1, and the median of the upper half is quartile 3.


Now subtract quartile 1 from quartile 3.


49 – 35 = 14


So the interquartile range of this data set is 14.

4 0
3 years ago
What is the image of F for a dilation with center (0, 0) and a scale factor of 10?
kogti [31]
F = (-3,3)
scale factor of 10

-3 * 10 = -30
3 * 10 = 30

answer : (-30,30)
6 0
3 years ago
Read 2 more answers
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