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tia_tia [17]
3 years ago
9

20 POINTS,, PLEASE HELP!!!

Mathematics
2 answers:
Sladkaya [172]3 years ago
7 0
Given points K'(1, -2) and L'(1, -4)...

where is point J' that produces a triangle J'K'L' congruent to JKL resulting from a rotation of 90 degrees clockwise around the point (1, -6)

J' (5, 0)
Mama L [17]3 years ago
3 0
Point J' would be located at (5,0)
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A culture started with 5000 bacteria. after 4 hours, it grew to 6000. Predict how many bacteria will be present after 17 hours
kykrilka [37]

Answer:

A culture started with 5000 bacteria. after 4 hours, it grew to 6000.

=> Increasing rate = difference/time = (6000 - 5000)/4 = 250 bacteria/hour

=> The number of bacteria after 17 hours:

N = 5000 + 250 x 17 = 9250 bacteria

Hope this helps!

:)

4 0
3 years ago
Read 2 more answers
PLEASE PLEASE HELP!!!
natka813 [3]

Answer:

398,765 books were sold

Step-by-step explanation:

How to get the answer:

1) Identify the given

  32,300 is percentage

  8.1 % is rate

  base (b) is missing

2) Solve

   b= p/r

   b= 32,300 / 8.1% or 0.081

   b= 398,765

3) Check

   398,765 x 8.1% = 32,299.97 or 32,300

5 0
3 years ago
Question shown in picture!!I tried it myself but it said i was wrong ♀️
timama [110]

The domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the x-axis.

The range is the set of possible output values, which are shown on the y-axis.

In the given graph, it shows that:

Domain (x-values): All reals

Range (y-values): y ≥ 2

5 0
11 months ago
What is the midpoint of the line segment with endpoints (-2,-2) and (4.6)?
erma4kov [3.2K]

Answer:

Step-by-step explanation:

(-2,2) ...x1 = -2 and y1 = 2

(4,6)..x2 = 4 and y2 = 6

midpoint formula :

m = ((x1 + x2) / 2 , (y1 + y2) / 2)

m = ((-2 + 4) / 2 , (2 + 6) / 2)

m = 2/2 , 8/2

m = (1,4) <===

5 0
3 years ago
The table gives a set of outcomes and their probabilities. Let A be the event "the outcome is
andriy [413]

Answer:0.2

Step-by-step explanation:

A=3

P(A)=P(3)

=0.2

7 0
3 years ago
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