Emilia solved this inequality as shown:

Francis is at the state fair. A fair concession stand is selling funnel cakes for $3.50 and deep-fried Oreos for $2.00. Write an

VladimirAG [237]

The equation that models the number of funnel cakes and Oreos he can buy is 3.50x + 2.0y = 42

Data given;

Cost of cakes = $3.50

Cost of Oreos = $2.00
The total amount spent = $42.00

<h3>What is the Equation</h3>

To solve this problem, we just need to write out an equation to show how he can spend $42.00 in the fair on Oreos and Cakes.

Let x represent the cakes

Let y represent the Oreos

The equation is thus;

$3.50x + 2.0y = 42.00$

The equation that shows the number of Cakes and Oreos can by is

3.50x + 2.0y = 42

Learn more about equation here;

brainly.com/question/13729904

3 0

2 years ago

a milk tank at a a dairy farm has the form of a rectangular prism. The tank is 3.5 feet wide. The width of the tank is 5/7 of it

AURORKA [14]

Answer:

17.5 cubic feet

1163.75 pounds

Step-by-step explanation:

Givens

L = 3.5 Given

W = 5/7 * 3.5 Divide by 7

W = 5 * 0.5 Combine

W = 2.5

H = 4/5 * w

H = 4/5 * 2.5

H = 4 * 0.5

H = 2

Volume

V = L * w * h

V = 3.5 * 2.5 * 2

V = 17.5

Weight

1 Cubic foot Milk = 66.5 pounds

17.5 cubic feet milk = x

1 / 17.5 = 66.5/ x

x = 17.5 * 66.5

x = 1164.75

7 0

3 years ago

A. Evaluate ∫20 tan 2x sec^2 2x dx using the substitution u = tan 2x.

irakobra [83]

Answer:

The integral is equal to $5\sec^2(2x)+C$ for an arbitrary constant C.

Step-by-step explanation:

a) If $u=\tan(2x)$ then $du=2\sec^2(2x)dx$ so the integral becomes $\int 20\tan(2x)\sec^2(2x)dx=\int 10\tan(2x) (2\sec^2(2x))dx=\int 10udu=\frac{u^2}{2}+C=10(\int udu)=10(\frac{u^2}{2}+C)=5\tan^2(2x)+C$ . (the constant of integration is actually 5C, but this doesn't affect the result when taking derivatives, so we still denote it by C)

b) In this case $u=\sec(2x)$ hence $du=2\tan(2x)\sec(2x)dx$ . We rewrite the integral as $\int 20\tan(2x)\sec^2(2x)dx=\int 10\sec(2x) (2\tan(2x)\sec(2x))dx=\int 10udu=5\frac{u^2}{2}+C=5\sec^2(2x)+C$ .

c) We use the trigonometric identity $\tan(2x)^2+1=\sec(2x)^2$ is part b). The value of the integral is $5\sec^2(2x)+C=5(\tan^2(2x)+1)+C=5\tan^2(2x)+5+C=5\tan^2(2x)+C$ . which coincides with part a)

Note that we just replaced 5+C by C. This is because we are asked for an indefinite integral. Each value of C defines a unique antiderivative, but we are not interested in specific values of C as this integral is the family of all antiderivatives. Part a) and b) don't coincide for specific values of C (they would if we were working with a definite integral), but they do represent the same family of functions.

3 0

3 years ago

Identify which statement about the mean of a discrete random variable is not true or state that they are all true.Choose the cor

pashok25 [27]

Answer:

A, C are true . B is not true.

Step-by-step explanation:

Mean of a discrete random variable can be interpreted as the average outcome if the experiment is repeated many times. Expected value or average of the distribution is analogous to mean of the distribution.

The mean can be found using summation from nothing to nothing x times Upper P (x) , i.e ∑x•P(x).

Example : If two outcomes 100 & 50 occur with probabilities 0.5 each. Expected value (Average) (Mean) : ∑x•P(x) = (0.5)(100) + (0.5)(50) = 50 + 25 = 75

The mean may not be a possible value of the random variable.

Example : Mean of possible no.s on a die = ( 1 + 2 + 3 + 4 + 5 + 6 ) / 6 = 21/6 = 3.5, which is not a possible value of the random variable 'no. on a die'

4 0

3 years ago

PLEASEEE

pantera1 [17]

Step-by-step explanation:

ggfsgkfxcxx CH jhdxnkrz

3 0

3 years ago