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nata0808 [166]
3 years ago
11

Find the value of the following (2n)!/n!​

Mathematics
1 answer:
Tcecarenko [31]3 years ago
6 0

Answer:

therefore, \frac{(2n)!}{n!}=(n+1)\cdot (n+2)\dots (2n)

Step-by-step explanation:

\frac{(2n)!}{n!} is interesting

if we write it out for n=4

\frac{(2n)!}{n!}=\frac{(2(4))!}{4!}=\frac{8!}{4!}=\frac{1\cdot 2\cdot 3\cdot 4\cdot 5 \cdot 6\cdot 7\cdot 8}{1\cdot 2\cdot 3\cdot 4}=5\cdot 6\cdot 7\cdot 8

try for n=3

\frac{(2n)!}{n!}=\frac{(2(3))!}{3!}=\frac{6!}{3!}=\frac{1\cdot 2\cdot 3\cdot 4\cdot 5 \cdot 6}{1\cdot 2\cdot 3}=4\cdot 5\cdot 6

we notice that the first n terms cancel out

therefore, \frac{(2n)!}{n!}=(n+1)\cdot (n+2)\dots (2n)

there is no further information given

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2 years ago
Do the product 40x500 and 40x600 have the same number of zeros
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No they do not have the same number of zeroes

Although the 2 products do seem like they might have the same number of zeroes, 40 x 500 and 40 x 600

both have 3 zeroes before multiplying

if we take the first 2 digits of the 2 numbers being multiplied to get an idea of the answer

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then theres an extra zero added

but if we take 40 x 600 - 4 x 6 = 24

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8 0
3 years ago
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Studentka2010 [4]

The numeric value of the expression -a² - 2bc - |c| for a = -3, b = -5 and c = 2 is of 9.

<h3>How to find the numeric value of an expression?</h3>

The numeric value of an expression is found replacing each letter by it's attributed value.

In this problem, the expression is:

-a² - 2bc - |c|

The attributed values are:

a = -3, b = -5 and c = 2

Hence the numeric value will be given by:

-a² - 2bc - |c| = -(-3)² - 2(-5)(2) - |2| = -(9) + 20 - 2 = -9 + 18 = 9.

More can be learned about the numeric value of an expression at brainly.com/question/14556096

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