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4 years ago

The volume of a cone is 35 ft3 and the cone’s height is 7 ft.

2 answers:

8 0

$The\ volume\ of\ a\ cone:V=\frac{1}{3}\pi r^2 H=\frac{1}{3}A_bH\\\\r-the\ radius\ \\H-the\ height\ of\ the\ cone\\A_b-area\ of\ the\ base\\----------------------\\\\V=35\ ft^3;\ H=7\ ft\\\\therefore\\\\\frac{1}{3}A_b\cdot7=35\\\\\frac{7}{3}A_b=35\ \ \ \ |divide\ both\ sides\ by\ \frac{7}{3}\to multiply\ both\ sides\ by\ \frac{3}{7}\\\\A_b=\frac{35}{1}\cdot\frac{3}{7}=\frac{5}{1}\cdot\frac{3}{1}=5\cdot3=\boxed{15\ (ft^2)}$

Serggg [28]4 years ago

6 0

Formula:

V = 1/3 * b * h

Plug in what we know:

35 = 1/3 * b * 7

Multiply 7 * 1/3:

35 = 2 1/3 * b

Multiply:

35 = 2 1/3b

Divide 2 1/3 to both sides:

b = 15

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According to the Fundamental Theorem of Algebra, the graph of f(x) = x2 - 4x + 3, has roots. From the graph we can see that it h

andreyandreev [35.5K]

Answer:

The graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

Step-by-step explanation:

Consider the given equation of graph $f(x)=x^2-4x+3$

According to the Fundamental Theorem of Algebra

For a given polynomial of degree n can have a maximum of n roots.

Thus, for the given equation $f(x)=x^2-4x+3$ the degree of polynomial is 2 , thus the function can have maximum of 2 roots.

We know at roots the value of function is 0 that is f(x) = 0,

Substitute f(x) = 0 , we get, $f(x)=x^2-4x+3=0$

This is a quadratic equation, $x^2-4x+3=0$

We first solve it manually and then check by plotting graph.

Quadratic equation can be solved using middle term splitting method,

here, -4x can be written as -x-3x,

$x^2-4x+3=0 \Rightarrow x^2-x-3x+3=0$

$\Rightarrow x(x-1)-3(x-1)=0$

$\Rightarrow (x-3)(x-1)=0$

Using zero product property, $a\cdot b=0 \Rightarrow a=0\ or \ b=0$

$\Rightarrow (x-3)=0$ or $\Rightarrow (x-1)=0$

$\Rightarrow x=3$ or $\Rightarrow x=1$

Thus, the two zero of f(x) are 3 and 1.

We can also see on graph attached below that the graph $f(x)=x^2-4x+3$ has two zeros namely 3 and 1.

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3 years ago

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zhuklara [117]

Answer:

3x+9

Step-by-step explanation:

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3 years ago

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Step-by-step explanation:

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3 years ago

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Verify that whether -2 and 3 are zeroes of the polynomial x^2-x=6 PLEASE HELP

Anna35 [415]

Answer:

Both give remainder 0 for the polynomial

Step-by-step explanation:

p(-2) = (-2)² - (-2) - 6

= 6 - 6 = 0

p(3) = (3)² - 3 - 6

= 9 - 9 = 0

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3 years ago

Question 1 (1 point) Divide using any method. -3x3 + 4.x2 + 2x – 5) (x - 2)

valkas [14]

Answer:Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of

Divide the highest order term in the dividend

by the highest order term in divisor

Multiply the new quotient term by the divisor.

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After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

Pull the next terms from the original dividend down into the current dividend.

Divide the highest order term in the dividend

−

by the highest order term in divisor

Multiply the new quotient term by the divisor.

The expression needs to be subtracted from the dividend, so change all the signs in

−

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

The final answer is the quotient plus the remainder over the divisor.

−

Step-by-step explanation:

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3 years ago