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Maru [420]
3 years ago
10

What occurs in a half-cell? oxidation or reduction, but not both reduction only oxidation only?

Chemistry
1 answer:
lesya692 [45]3 years ago
5 0
Answer: In a half-cell is where occurs the either oxidation (loss of electrons) or reduction (gain of electrons) but not both.

Explanation:

1) In an electrolitic cell you can identify two half-cells.

2) In one half-cell occurs the oxidation

3) In the other half-cell occurs the reduction.

4) The half-cell where oxidation occurs is the anode.

In the anode the spieces increase its oxidation number, which is what oxidation means. Increasing the oxidation number means that the spieces is losing electrons.


5) The half-cell where reduction occurs is the cathode.

Reduction is the reduction of the oxidation number and this occurs due to the gain of electrons.


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For the following reaction, 5.78 grams of chlorine gas are mixed with excess iron. The reaction yields 6.79 grams of iron(III) c
NeX [460]

Answer:

a. Theoretical yield = 8.81 g

b. 77 %

Explanation:

We begin from the reaction:

2Fe (s) + 3Cl₂ (g) → 2FeCl₃ (s)

and the excess is the iron, so the limiting reagent is the chlorine.

We convert mass to moles → 5.78 g / 70.90 g/mol = 0.0815 mol

Ratio is 3:2 so we think this:

From 3 moles of chlorine, I can produce 2 moles of Iron (III) chloride

Then 0.0815 moles would produce (0.0815 . 2) /3 = 0.0543 moles

This is the theoretical yield. We convert the moles to mass:

0.0543 mol . 162.2 g /mol = 8.81 g

If the reaction yields 6.79 g of FeCl₃ and the theoretical yield is 8.81 g ,we can obtain the percent yield: (6.79 / 8.81) . 100 = 77 %

5 0
3 years ago
Covalent bonds are formed from the sharing of valence electrons
makvit [3.9K]

Answer:true

Explanation:

In covalent bond, lone pair of electrons are shared by the reacting species inorder to achieve a stable duplet or octet condition.as a result, molecules and not ions are formed

3 0
4 years ago
Read 2 more answers
What is the oxidation state of an individual nitrogen atom in nh4oh ? express the oxidation state numerically (e.g., +1)?
Nonamiya [84]
In NH4OH, the compounds that make it up are NH4+ and OH-
Therefore N exists in the ammonium form.
In the ammonium ion 4H atoms are connected to N. 
 N is more electronegative than H, therefore when H bonds to N, H is the more positive atom therefore each H has a charge of +1, since there are 4 H atoms the charge contributed by the 4H atoms are +1 * 4 = +4
the overall charge of NH4 is +1
Charge of N (+) +4 =  +1
Charge of N = +1 - 4
Therefore oxidation state of N in NH4 is  = -3
6 0
4 years ago
What is the product of the reduction of an aldehyde?
Elza [17]

Answer:

Achol

Explanation:

Reduction of other aldehydes gives primary alcohols. Reduction of ketones gives secondary alcohols. The acidic work-up converts an intermediate metal alkoxide salt into the desired alcohol via a simple acid base reaction.

5 0
3 years ago
How to answer this ?
tamaranim1 [39]

Answer:

as follow

Explanation:

2

a acceptor

b Donor electron

3

A. MgBr2 B. Na2O

C. HCl D. AlCl3

E. K3N F. CaS

* the number is under the charactor/atoms

4 0
3 years ago
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