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professor190 [17]
3 years ago
12

The specific heat for liquid ethanol is 2.46 J/(g•°C) when 655j are addedto a sample of ethanol temp rises from 18.2 to 32.8 wha

t is the mass of the ethanol sample
Chemistry
1 answer:
borishaifa [10]3 years ago
6 0
Thermodynamics are very important to understand for a number of reasons. The equation we use for specific heat is:

Q = m*s*(delta T)

Where Q is the heat, m is the mass of the substance, s is the specific heat of the substance, and (delta T) is the change in temperature.


To solve this problem, we will have to manipulate our equation to solve for m. After manipulating variables, we end with:

m = Q / [s * (delta T)]


Next, let’s organize ourselves and see what values the problem has given us:
- Q is 655J
- s is 2.46 J / g * °C
- (delta T) is 32.8 - 18.2 = 14.6°C
- m = ?


Now, all we need to do is plug in our values to solve for m:

m = (655J)/[(2.46J/g*°C)*(14.6°C)
m = 18.2 g



The mass of the ethanol sample is 18.2g.

Hopefully this helps you!

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Please help I really appreciate it thank you ❤️
Feliz [49]

II. sulfur (S) and carbon (C)

and

III. fluorine (F) and oxygen (O)

will form covalent bonds, so the answer will be:

e. II and III

Explanation:

To know is what type of bond is formed between atoms we need to look at the electronegativity difference between the atoms.

If the electronegativity difference is less than 0.4 there is a nonpolar covalent bond.

If the electronegativity difference is between 0.4 and 1.8 there is a polar covalent bond. (if is a metal involved we consider the bond to be ionic)

If the electronegativity difference is greater then 1.8 there is an ionic bond.

We have the following cases:

I. lithium (Li) and sulfur (S)

electronegativity difference = 2.5 (S) - 1 (Li) = 1.5 but because there is a metal involved the bond will be ionic

II. sulfur (S) and carbon (C)

electronegativity difference = 2.5 (S) - 2.5 (C) = 0 so the bond will be nonpolar covalent

III. fluorine (F) and oxygen (O)

electronegativity difference = 4 (F) - 3.5 (O) = 0.5 so the bond will be polar covalent bond.

Learn more about:

covalent and ionic bonds

brainly.com/question/1802971

#learnwithBrainly

3 0
4 years ago
Round off or add zeros to the following calculated answers to give a final answer with three significant figures
sesenic [268]
In this case, 58.703 has five significant figures because the 3 at the end is significant and therefore makes the 0 significant as well. Since there are 5 significant figures, we need to round off the 7 to get 58.7, which has three significant figures.

Hope this helps.
8 0
3 years ago
Draw a complete Lewis structure for the conjugate acid of nitromethane that shows all bonds, unshared electron pairs, and minimi
Marysya12 [62]
I am pretty sure that is exactly what you need. Proton in there should either gain or loss from the carbon, as there is <span>resonance stabilization. Do hope you still need the answer, because this one is really helpful. Regards!</span>

8 0
4 years ago
When placed in strange situations without their artificial mothers, the Harlows' infant monkeys demonstrated signs of:
Semenov [28]

Answer:

A)insecure attachment.

Explanation:

There are many people or animals that are only capable of creating insecure attachment links. Put simply, this type of attachment is one in which the bond is contaminated by fear. This is expressed, mainly, as withdrawal in the relationship with others or confusing emotions, of dependence and rejection.

Most psychologists argue that insecure attachment is developed in early childhood. It would be a consequence of the relationship established by people who have this pattern of attachment with their figures or people of confidence in childhood. Those first links are the basis of those who will establish later.

5 0
4 years ago
The conversion of methyl isonitrile to acetonitrile in the gas phase at 250 °C CH3CN(g) is first order in CH3NC with a rate cons
nadya68 [22]

Answer: The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

Explanation:

Expression for rate law for first order kinetics is given by:

t=\frac{2.303}{k}\log\frac{a}{a-x}

where,

k = rate constant = 3.00\times 10^{-3}s^{-1}

t = age of sample = ?

a = let initial amount of the reactant = 5.45\times 10^{-2}M

a - x = amount left after decay process = 1.56\times 10^{-2}M

t=\frac{2.303}{3.00\times 10^{-3}}\log\frac{5.45\times 10^{-2}}{1.56\times 10^{-2}}

t=416s

The concentration of CH_3NC will be 1.56\times 10^{-2}M after 416 seconds have passed.

5 0
3 years ago
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