Solution :
According to the Graham's law of diffusion, we know that, the rate of the diffusion varies inversely to the molar mass of the gas, i.e.
Rate of diffusion, 
where, the 'M' is the molar mass of the gas.
Now in the case of the isotopes of the Krypton,
Atomic mass of 
= 80 AMU
Atomic mass of 
= 82 AMU
Atomic mass of 
= 83 AMU
So the ratio of the rate of diffusion of the three isotopes are :
Dividing the above three with the smallest number among the three i.e. 0.10976, we get the relative rates of diffusion.
∴
= 1.02 : 1.01 : 1
Hence the relative rate of diffusion are :
Answer:
yes it is balanced.
Explanation:
when you are balancing an equation you look at the elements or compounds on the reactants and product side, which must have the same number of elements on both sides. like the question above;
2 potassium on the reactant and product side.
2 chlorine on the reactant and product side.
6 oxygen on the reactant and product side.
Answer:
average atomic mass = 46.8509984 amu
Explanation:
To get the average atomic mass, we will follow these steps:
1- multiply the atomic mass of each isotope by its percentage of abundance
2- add the products
We are given that:
1- The first isotope has an atomic mass of 45.95293 and percentage of abundance equals 72%
2- The second isotope has an atomic mass of 47.94795 and percentage of abundance equals 11%
3- The third isotope has an atomic mass of 49.94479 and percentage of abundance equals 17%
Following the mentioned steps, we can get the average atomic mass as follows:
average atomic mass = (45.95293)(0.72)+(47.94795)(0.11)+(49.94479)(0.17)
= 46.8509984 amu
Hope this helps :)
The object can no longer be returned to its original self, like ashes can't turn back to wood. The color changes, and bubbles.Also odor change, and gas formation.
Answer:
Here's what I get.
Explanation:
The MO diagrams of KrBr, XeCl, and XeBr are shown below.
They are similar, except for the numbering of the valence shell orbitals.
Also, I have drawn the s and p orbitals at the same energy levels for both atoms in the compounds. That is obviously not the case.
However, the MO diagrams are approximately correct.
The ground state electron configuration of KrF is
KrF⁺ will have one less electron than KrF.
You remove the antibonding electron from the highest energy orbital, so the bond order increases.
The KrF bond will be stronger.
