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2 years ago

You decide to clean the bathroom. You notice that the shower is covered in a strange green slime. You try

Chemistry

1 answer:

musickatia [10]2 years ago

7 0

Answer:

Use either a vinegar, Borax, or bleach solution in a spray bottle to tackle the mold. Simply spray the solution on showers, baths, basins, tiles, grout, or caulking. Then use either a cleaning cloth or a toothbrush to remove the slime

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Can somebody in 8thgarde help me with Examining Molecules and compounds ?

MakcuM [25]

I might be able to. I am in 8th grade science.

5 0

2 years ago

6 C(s) + 3 H2(g) → 2 C6H6(l) Δ H = 49 kJ TRUE or FALSE

VMariaS [17]

Answer:

True => ΔH°f for C₆H₆ = 49 Kj/mole

Explanation:

See Thermodynamic Properties Table in appendix of most college level general chemistry texts. The values shown are for the standard heat of formation of substances at 25°C. The Standard Heat of Formation of a substance - by definition - is the amount of heat energy gained or lost on formation of the substance from its basic elements in their standard state. C₆H₆(l) is formed from Carbon and Hydrogen in their basic standard states. All elements in their basic standard states have ΔH°f values equal to zero Kj/mole.

7 0

3 years ago

Theory is often used as a synonym for idea in everyday life.

Rasek [7]

I think B. As an idea is just a way that could be possible

8 0

2 years ago

Differentiate between Halogens and insert gases

jasenka [17]

Answer:

An inert gas is one that does not undergo chemical reactions

Noble gases refers to the right most group of the periodic table composed of helium, neon, argon, krypton, xenon, and radon. As you might have seen as an example in class, some noble gases can form chemical compounds, such as XeF4.

or to say:

Halogens and noble gases are two different groups of elements that can be seen on the periodic table. Halogens are found in group 17 and include fluorine, chlorine, bromine, iodine and astatine. Noble gases make up group 18, and include helium, neon, argon, krypton, xenon and radon.

6 0

3 years ago

During a titration the following data were collected. A 50.0 mL portion of an HCl solution was titrated with 0.500 M NaOH; 200.

Travka [436]

Answer: The mass of HCl present in 500 mL of acid solution is 36.5 grams

Explanation:

To calculate the concentration of acid, we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is HCl

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is NaOH.

We are given:

$n_1=1\\M_1=?M\\V_1=50.00mL\\n_2=1\\M_2=0.500M\\V_2=200.mL$

Putting values in above equation, we get:

$1\times M_1\times 50.00=1\times 0.500\times 200\\\\M_1=\frac{1\times 0.500\times 200}{1\times 50.00}=2M$

To calculate the mass of solute, we use the equation used to calculate the molarity of solution:

$\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}$

Molar mass of HCl = 36.5 g/mol

Molarity of solution = 2 M

Volume of solution = 500 mL

Putting values in above equation, we get:

$2mol/L=\frac{\text{Mass of solute}\times 1000}{36.5g/mol\times 500}\\\\\text{Mass of solute}=\frac{2\times 36.5\times 500}{1000}=36.5g$

Hence, the mass of HCl present in 500 mL of acid solution is 36.5 grams

4 0

2 years ago