Question:
Each liter of air has a mass of 1.80 grams. How many liters of air are contained in 2.5 x103) kg of air?
Answer:
11.48106 L
Answer:
A)a scientist exploring evidence from other fields of science to support findings
Explanation:
hope this helps.
Answer : The mass of occupy 30.3 L under the same conditions will be, 24.9 grams.
Explanation :
First we have to calculate the moles of
Now we have to calculate the moles of in 30.3 L by using Avogadro's law.
Avogadro's law : It is defined as the volume of gas is directly proportional to the number of moles of gas at constant pressure and temperature.
or,
where,
= initial volume of gas = 6.21 L
= final volume of gas = 30.3 L
= initial moles of gas = 0.16 mol
= final temperature of gas = ?
Now put all the given values in the above equation, we get:
Now we have to calculate the mass of
Molar mass of = 32 g/mol
Therefore, the mass of occupy 30.3 L under the same conditions will be, 24.9 grams.
S + 2HNO3---> H2SO4 + 2NO