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erma4kov [3.2K]
3 years ago
6

Which gas is not known as green house gas

Chemistry
1 answer:
Bas_tet [7]3 years ago
6 0

Carbon dioxide is a main greenhouse gas, found in car exhaust pipes. Methane and nitrous oxide is another type of greenhouse gas. Oxygen is the only clean gas out there because we need it to survive. Therefore, the only gas that is not a greenhouse gas is (c) oxygen.

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Please help this is due soon and I’ll mark you brainiest if you can help
attashe74 [19]

Answer:

I think it's either A or D I'm not sure hope that I helped you.

7 0
2 years ago
What volume is occupied by 16.4 g of mercury? The density of mercury is 13.6 g/mL
NeTakaya

Answer:

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Explanation:

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3 0
3 years ago
How many moles of atoms are in 5.00 g of 13C
Illusion [34]
  <span>Mr = 13 g / mol 
mass = 5 g 
Mol = 5/13 mol :)</span>
7 0
3 years ago
Given LiCl, NaCl, KCl, MgCl2, and SrCl2, arrange the compounds in order of increasing lattice energy.
Oksanka [162]

Answer:-  KCl

Explanations:- Lattice energy depends on two factors, charge and size.

High charge and small size gives higher lattice energy where as low charge and bigger size gives lower lattice energy.

in LiCl, NaCl and KCl, the anion is same and also the charges for Li, Na and K are also same. The deciding factor here is the size of cations. Since the size increases as we move down a group, the order of size of these three atoms is Li<Na<K.

The order of lattice energy is exactly opposite as it's increases as the size decreases.

Now, if we look at magnesium chloride and strontium chloride then again the anion is common but the metals have higher charge as compared to the alkali metals(Li, Na and K). So, lattice energy values must be higher for these two compounds. If we compare Mg and Sr then size of Mg is smaller and so the lattice energy would be greater for this.

Hence, the increasing order of lattice energy is KCl .

4 0
3 years ago
Read 2 more answers
1. Calculate the energy of a photon with a frequency of 3x1015 Hz.<br> ?????
Afina-wow [57]

Answer:

1.99 x 10⁻¹⁸J

Explanation:

Given parameters:

Frequency of the wave  = 3 x 10¹⁵Hz

Unknown:

Energy of the photon  = ?

Solution:

To solve this problem, we use the expression below;

     E  = hf

Where E is the energy, h is the Planck's constant and f is the frequency

Now insert the parameters and solve for E;

     E  = 6.63 x 10⁻³⁴ x 3 x 10¹⁵ = 19.9 x 10⁻¹⁹J or 1.99 x 10⁻¹⁸J

6 0
3 years ago
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