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3 years ago

What is the Charge of a neutral atom after 1 electron is taken away?

Chemistry

1 answer:

mario62 [17]3 years ago

6 0

Answer:

Explanation:

An atom is considered to be neutral before losing or gaining any electrons. They are neutral in charge because they initially have the same number of protons (with charge of +1 each) and electrons (with a charge of -1 each).

Consider charge in an electron like a balance, with positively charged protons on one side and negatively charged electrons on the other. When you have the same number of each, there is equal amounts of positive and negative charge so the atom is neutral with a charge of zero.

For example, potassium has 19 protons, and 19 electrons. This means it has 19 positive charges and 19 negative charges. If you take away one electron, it now has 19 positive charges and 18 negative charges. So there is one more positive charge than negative, which means it is now an ion (a charged atom) with a charge of +1.

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Nickel and carbon monoxide react to form nickel carbonyl, like this: (s)(g)(g) At a certain temperature, a chemist finds that a

horsena [70]

The question is incomplete, here is the complete question:

Nickel and carbon monoxide react to form nickel carbonyl, like this:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

At a certain temperature, a chemist finds that a 2.6 L reaction vessel containing a mixture of nickel, carbon monoxide, and nickel carbonyl at equilibrium has the following composition:

Compound Amount

Ni 12.7 g

CO 1.98 g

$Ni(CO)_4$ 0.597 g

Calculate the value of the equilibrium constant.

<u>Answer:</u> The value of equilibrium constant for the reaction is 2448.1

<u>Explanation:</u>

We are given:

Mass of nickel = 12.7 g

Mass of CO = 1.98 g

Mass of $Ni(CO)_4$ = 0.597 g

Volume of container = 2.6 L

To calculate the number of moles for given molarity, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Given mass of solute}}{\text{Molar mass of solute}\times \text{Volume of solution (in L)}}$

$\text{Equilibrium concentration of nickel}=\frac{12.7}{58.7\times 2.6}=0.083M$

$\text{Equilibrium concentration of CO}=\frac{1.98}{28\times 2.6}=0.0272M$

$\text{Equilibrium concentration of }Ni(CO)_4=\frac{0.597}{170.73\times 2.6}=0.00134M$

For the given chemical reaction:

$Ni(s)+4CO(g)\rightarrow Ni(CO)_4(g)$

The expression of equilibrium constant for the reaction:

$K_{eq}=\frac{[Ni(CO)_4]}{[CO]^4}$

Concentrations of pure solids and pure liquids are taken as 1 in equilibrium constant expression.

Putting values in above expression, we get:

$K_{eq}=\frac{0.00134}{(0.0272)^4}\\\\K_{eq}=2448.1$

Hence, the value of equilibrium constant for the reaction is 2448.1

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4 years ago

With the given chemical compounds, what is the balanced chemical equation when lit with fire?

Alchen [17]

Answer:

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3 years ago

If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa,

Feliz [49]

Answer: The volume of the balloon at the center of the typhoon is 41.7L.

Note: The complete question is given below;

If a small weather balloon with a volume of 40.0 L at a pressure of 1.00 atmosphere was deployed at the edge of Typhoon Odessa, what was the volume of the balloon when it reached the center?

The severity of a tropical storm is related to the depressed atmospheric pressure at its center. In August 1985, Typhoon Odessa in the Pacific Ocean featured maximum winds of about 90 mi/hr and pressure that was 40.0 mbar lower at the center than normal atmospheric pressure. In contrast, the central pressure of Hurricane Andrew (pictured) was 90.0 mbar lower than its surroundings when it hit south Florida with winds as high as 165 mi/hr.

Explanation:

Since no temperature changes were given, it is assumed to be constant. Therefore, Boyle's law which describes the relationship between pressure and volume is used to determine the new volume at the center of Typhoon Odessa. Mathematically, Boyle's law states that; P1V1 = P2V2

Assuming 1atm = 1 bar, 1mbar = 0.001atm, 40mbar = 0.040atm

P1 = 1.0atm, V1 = 40.0L, P2 = 1atm - 0.040atm = 0.960atm, V2 = ?

Using P1V1 = P2V2

V2 = P1V1/P2

V2 = 1.0 * 40.0 / 0.96

V2 = 41.67L

Therefore, the volume of the balloon at the center of the typhoon is 41.7L.

5 0

3 years ago

Write the equilibrium-constant expression for the reactionA(s)+3B(l)↽−−⇀2C(aq)+D(aq)A(s)+3B(l)↽−−⇀2C(aq)+D(aq)in terms of [A], [

Ilia_Sergeevich [38]

Answer: