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3 years ago

Write an equation of the line passing through each of the following pairs of points. (4,-8), (0,2)

Mathematics

1 answer:

ollegr [7]3 years ago

7 0

Step-by-step explanation:

m= $\frac{2-(-8)}{0-4}$ = $\frac{10}{-4}$ = -2.5

this may be right but I do not know

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A company paid $72 for 2 cases of printer paper each case contained 12 packages of paper next month the company's office manager

Tems11 [23]

To figure out the cost for 180 packages, you must first calculate how many packages they bought for $72. Since each case holds 12 packages, for $72, the company bought 24 packages (12×2). Then you have to divide 24 into 180 to figure out the cost for those 180 packages and get 7.5. To get the cost of the 180 packages, you must multiply 7.5 (the number of 24 packages that go into 180) by 72 (the cost of one group of 24 packages). You then get 540. The company must pay $540 for the 180 packages.

7 0

3 years ago

Belinda wants to buy 5 pictures to hang in her family room . If each picture costs $30.90 how much will it cost her to buy 5? Ju

kow [346]

Ur answr would be 154.50 because if u do 30.90 5 times or times 30.90 by 5 its 154.50

6 0

3 years ago

Solve the inequality for x. <br><br> x-c/d > y (for d > 0)

Mnenie [13.5K]

Step-by-step explanation:

x-c/d>y

d(x)-d(c/d)>d(y)

dx-cd-d^2>dy

dx>dy+cd+d^2

dx>d(y+c+d)

dx/d>d(y+c+d)/d

x>d(y+c+d)/d

8 0

3 years ago

Which of the following functions f : {0, 1, 2, 3} ! {0, 1, . . . , 7} are one-to-one?

allsm [11]

Answer:

1. No.

$f(0)=0\\1^2=1; \text{then } f(1)=1\\2^2=4\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^2=9\equiv 1 \text{mod 8 }; \text{then } f(3)=1$

Since f(1)=f(3) and $1\neq 3$ then f isn't one-to-one.

2. No

$f(0)=0\\1^3=1\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3=8\equiv 0\text{ mod 8}; \text{then } f(2)=0\\3^3=27\equiv 3 \text{ mod 8}; \text{then } f(3)=3$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

3. No

$0^3-8=-8\equiv 0\text{ mod 8}; \text{then } f(0)=0\\1^3-8=-7\equiv 1\text{ mod 8}; \text{then } f(1)=1\\2^3-8=0\equiv 0 \text{ mod 8}; \text{then } f(2)=0\\3^3-8=27-8=19\equiv 3 \text{ mod 8}; \text{then } f(3)=3\\$

Since f(0)=f(2) and $0\neq 2$ then f isn't one-to-one.

4. Yes

$0^3+2*0=0; \text{then } f(0)=0\\1^3+2*1=3\equiv 3\text{ mod 8}; \text{then } f(1)=3\\2^3+2*2=8+4=12\equiv 4 \text{ mod 8}; \text{then } f(2)=4\\3^3+2*3=27+6=33\equiv 1\text{ mod 8}; \text{then } f(3)=1$

Since $f(0)\neq f(1)\neq f(2) \neq f(3)$ , then f is one-to-one

5. Since f(1)=f(3) and $1\neq 3$ then, f isn't one-to-one

3 0

3 years ago

What is 20.1000÷300000

horrorfan [7]

The answer would be .0333 hope this helped

7 0

3 years ago

Read 2 more answers