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igomit [66]
2 years ago
15

How do I find the missing value?

Mathematics
1 answer:
Usimov [2.4K]2 years ago
4 0
Hope the given solution helps:) Have a great day. Do mark me brainliest if it has really helped you. Thank You.

You might be interested in
Write the slope-intercept form of the equation of each line given the slope and y-intercept
yuradex [85]

Answer:

y=4/3x-5.  

y=-5x+1

4 0
2 years ago
I need help............​
Alexxandr [17]

Problem 35

The bar graph is shown below

You simply draw various rectangles such that the heights represent the frequency of each animal type.

Eg: there are 20 elephants, so the "elephant" bar is 20 units tall.

You can make the bar graph by hand, or use spreadsheet software. I recommend going with software (if you can).

=======================================================

Problem 36

1 book = 20 mm thickness

5 books = 5*20 = 100 mm thickness

1 paper = 0.016 mm thickness

5 papers = 5*0.016 = 0.08 mm thickness

total thickness = 100+0.08 = 100.08 mm

<h3>Answer: 100.08 mm</h3>

=======================================================

Problem 37

121/11 = 11

121 = 11*11

If we say 11+11+11+...+11, and have 11 copies of these values added, then we get to a sum of 121

This is probably the easiest way to get the answer assuming repeated values are allowed.

You can stop here if your teacher allows you to use repeated values. If not, then move onto the next section.

-----------

If your teacher requires you to add 11 <u>different</u> numbers, then you can follow this procedure

  1. Write out eleven copies of "11" in a sequence
  2. Subtract 2 from the first "11" (to get 9) and add it to the last copy of "11" (to get 13)
  3. Subtract 4 from the second "11" (to get 7) and add it to the second to last copy of "11" (to get 15)
  4. Subtract 6 from the third "11" (to get 5) and add it to the third to last copy of "11" (to get 17)
  5. Subtract 8 from the fourth "11" (to get 3) and add it to the fourth to last copy of "11" (to get 19)
  6. Finally, subtract 10 from the fifth "11" (to get 1) and add it to the fifth to last copy of "11" (to get 21)

After carefully following those steps, you'll get this sequence (in the exact order shown):

{9, 7, 5, 3, 1, 11, 21, 19, 17, 15, 13}

There are three properties to notice of this sequence

  1. It's composed of two decreasing arithmetic sequences {9, 7, 5, 3, 1} and {21, 19, 17, 15, 13}
  2. The 11 in the middle hasn't been changed from the original sequence of nothing but "11"s.
  3. You should find that the terms of this new sequence add to 121.

That sequence we got sorts to {1, 3, 5, 7, 9, 11, 13, 15, 17, 19, 21}

and we can say 1+3+5+7+9+11+13+15+17+19+21 = 121

<h3>Answer: 1+3+5+7+9+11+13+15+17+19+21 = 121</h3>

5 0
2 years ago
Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°
natima [27]

 

\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0

.

\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}

 

 

5 0
3 years ago
What is the value of x? Round your answer to the nearest tenth if necessary.
katen-ka-za [31]

So to start off:

The equation you will want to use for the hypotenuse is

A (squared) + B (squared) = C (squared)

So you will want to fill in the equation like so:

7(7) + 4(4) = C (squared)

So now that you have your information filled out, put it all together!

49 + 16 = 65

Now don't forget that the 65 is SQUARED!

You will want to use the SQUARE ROOT method to help with that!

So what you will want to do is think of the numbers that are PERFECT SQUARES.

A perfect square consist of

Here is the list of perfect squares 1-10:

1 x 1 = 1

2 x 2 = 4

3 x 3 = 9

4 x 4 = 16

5 x 5 = 25

6 x 6 = 36

7 x 7 = 49

8 x 8 = 64

9 x 9 = 81

So look closely at these perfect squares, Do you see where 65 will lie?

It will lie between 8 and 9.

So you will do the square root now.

√65

The answer will come out as:

<span>8.06225775</span>

<span>You will then round it to the nearest tenths place (one after the decimal)</span>

You will look at the two numbers behind the decimal which is

0.6.

As you know,(If you round the tenths place), if the number in the hundredths is 5 or HIGHER. It will round up the number in the tenths place to 1.

So as we know 6 is higher than 5 so your answer would be:

8.1

I hope this helped! :)

>^.^<

(      )~


3 0
3 years ago
Read 2 more answers
If 15 litres of paint covers an area of 250 m2, what area (in m2) will 20 litres of paint cover?
Korvikt [17]

Answer: 333.33m²

Step-by-step explanation:

Since we are informed that 15 litres of paint covers an area of 250 m2, the the area that 1 liter of paint will cover will be:

= 250m²/15

= 16.666667m²

Therefore, the area that 20 litres of paint will cover will be:

= 16.666667m² × 20

= 333.33m²

8 0
2 years ago
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