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3 years ago

(h+k)(2)=? (h-k)(3)=? 3h(2)+2k(3)=?

Mathematics

1 answer:

marusya05 [52]3 years ago

8 0

Answer:

see explanation

Step-by-step explanation:

(h + k)(x) = h(x) + k(x), thus

h(x) + k(x)

= x² + 1 + x - 2 = x² + x - 1 , then

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

----------------------------------------------------

(h - k)(x) = h(x) - k(x), thus

h(x) - k(x)

= x² + 1 - (x - 2) = x² + 1 - x + 2 = x² - x + 3, then

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

-----------------------------------------------------

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

Thus

3h(2) + 2k(3)

= 3(5) + 2(1) = 15 + 2 = 17

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Answers:
a = 1
b = $\frac{1}{16}$ 
c = $\frac{1}{256}$
d = 1
e = $\frac{4}{9}$
f = $\frac{16}{81}$

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