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Ksivusya [100]
3 years ago
11

(h+k)(2)=? (h-k)(3)=? 3h(2)+2k(3)=?

Mathematics
1 answer:
marusya05 [52]3 years ago
8 0

Answer:

see explanation

Step-by-step explanation:

(h + k)(x) = h(x) + k(x), thus

h(x) + k(x)

= x² + 1 + x - 2 = x² + x - 1 , then

(h + k)(2) = 2² + 2 - 1 = 4 + 2 - 1 = 5

----------------------------------------------------

(h - k)(x) = h(x) - k(x), thus

h(x) - k(x)

= x² + 1 - (x - 2) = x² + 1 - x + 2 = x² - x + 3, then

(h - k)(3) = 3² - 3 + 3 = 9 - 3 + 3 = 9

-----------------------------------------------------

h(2) = 2² + 1 = 4 + 1 = 5

k(3) = 3 - 2 = 1

Thus

3h(2) + 2k(3)

= 3(5) + 2(1) = 15 + 2 = 17

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Answer:

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Step-by-step explanation:

If 8 out of 21 are WOODWINDS, we can say:

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This is the ratio.

Now, there are 63 total instruments. We need to find how many ARE NOT woodwinds. We equate the ratio found (13 out of 21) with total 63 instruments and find "x" [let x be number of instruments that are NOT woodwinds].

Shown below:

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