Answer:
Step-by-step explanation:
Rationalize the denominator of b. So, multiply the numerator and denominator by 

Now, find a +b

Combine like terms

Now find (a + b)²
(a +b)² = 

Hint: 
Answer:

Step-by-step explanation:



if x= 7 what is the value of x-4
7 - 4
=3
if y=3 what is the value of 8y
8 x 3
= 24
if x=7 what is the value of 3x-4
(3 x 7) - 4
= 17
if x=7 and y=3 what is the value of 2x-7y
(2 x 7) -(7 x 3)
= - 7
if x=7 and y=3 what is the value of 4y-X
(4 x 7) - 3
= 25
Hope this helps
<span>if point A( 2,2) is reflected across the line Y then the new position A' is (-2,2) and the distance AY = distance A'Y
if A is reflected across line R it is now at point B and the distance AR = distance BR
lets say the point A(2,2) was perpendicular to the line R at the point (1, 4) then when reflected the point A now at location B will have coordinates</span><span>when flipped over a line of reflection the lengths are still the same
the point to the line of reflection is the same length as the line of reflection to the reflected position
the distance from the original point to the reflected point is twice the distance from the original point to the line of reflection
cannot see your polygon.
here is an example
</span>
Answer:
0.216 has exactly one cube root, which is 0.6.
Step-by-step explanation:
Note that the third root of 0.216 is 0.6, obtained on a calculator by typing in 0.216^(1/3). Verify this root by cubing 0.6: 0.6*0.6*0.6 = 0.216. Thus, 0.216 has exactly one cube root.