The answer is 40% I believe because if you add 18+12 you get 30 and 12/30 when converted is 40%
Answer:
I believe the answer is D
Step-by-step explanation:
Inverse proportion occurs when one value increases and the other decreases
D is the answer because as each cat eats the same amount of dry cat food, there is less dry cat food in the bag; so this is why D best answers the question.
Hope this helps!
x-coordinates for the maximum points in any function f(x) by f'(x) =0 would be x = π/2 and x= 3π/2.
<h3>How to obtain the maximum value of a function?</h3>
To find the maximum of a continuous and twice differentiable function f(x), we can firstly differentiate it with respect to x and equating it to 0 will give us critical points.
we want to find x-coordinates for the maximum points in any function f(x) by f'(x) =0
Given f(x)= 4cos(2x -π)
![f'(x) = 0\\- 4sin(2x -\pi ) =0\\\\sin (2x -\pi ) =0 \\2x -\pi = k\pi ... k in Z](https://tex.z-dn.net/?f=f%27%28x%29%20%3D%200%5C%5C-%204sin%282x%20-%5Cpi%20%29%20%3D0%5C%5C%5C%5Csin%20%282x%20-%5Cpi%20%29%20%3D0%20%5C%5C2x%20-%5Cpi%20%20%3D%20k%5Cpi%20...%20%20k%20in%20Z)
In general ![x=(k+1)\pi /2](https://tex.z-dn.net/?f=x%3D%28k%2B1%29%5Cpi%20%2F2)
from x = 0 to x = 2π :
when k =0 then x = π/2
when k =1 then x= π
when k =2 then x= 3π/2
when k =3 then x=2π
Thus, X-coordinates of maximum points are x = π/2 and x= 3π/2
Learn more about maximum of a function here:
brainly.com/question/13333267
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A) For both sets A and B, calculating the mean, range, and quartiles are a good way of measuring the center and spread. Using standard deviation may not be the best because we do not know whether the distributions are normal or not.
b) For set A, the lowest value is 63, while the highest is 86. An estimate for the mean, based on the average of these, is 74.5. Most of the 70+ values are below 74.5, so we may guess that the mean will be above the median.
For set B, the lowest is 63, while the maximum is 95. The estimated mean would be 79. But since there are more values on the 80+ and 90+ side, the median is likely to be higher than 79.
c) For set A, the mean is 74.79, while the median is 73, therefore the mean is above the median, and the prediction in part b is correct.