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3 years ago

Help will give Brainly points

Mathematics

2 answers:

Misha Larkins [42]3 years ago

7 0

Answer:

Step-by-step explanation:

e-lub [12.9K]3 years ago

5 0

Answer: no
explanation:
Because the shape changed

good luck!

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5. Determine whether the

BARSIC [14]

Step-by-step explanation:

5. Determine whether the

-2

-1

Is it a linear quadratic or exponential

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3 years ago

I will Make you brainiest!!!!!

love history [14]

Answer:

i will do it :)

Step-by-step explanation:

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2 years ago

5. solve for x

miss Akunina [59]

Answer:

x = 17, MN = 11

Step-by-step explanation:

Given 2 secants from an external point to a circle, then

The product of the external part and the whole of one secant is equal to the product of the external part and the whole of the other secant.

(5)

7(7 + x) = 8(8 + 13) = 8 × 21 = 168 ( divide both sides by 7 )

7 + x = 24 ( subtract 7 from both sides )

x = 17

(6)

9(9 + 2x - 7) = 10(10 + 8)

9(2x + 2) = 10 × 18 = 180 ( divide both sides by 9 )

2x + 2 = 20 ( subtract 2 from both sides )

2x = 18 ( divide both sides by 2 )

x = 9

Then

MN = 2x - 7 = 2(9) - 7 = 18 - 7 = 11

7 0

3 years ago

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300. The

zubka84 [21]

Answer:

the variance of the refund payment to the couple = 9463.394

Step-by-step explanation:

Given that :

A couple book a cruise to Alaska that promises to refund 100 per day of rain on the seven day cruise up to a maximum of 300.

It is possible that the couple won't be able to refund up 100 per day or more than 100 per day.

SO; let assume that the refund payment happens to be 0, 100,200, 300

Let X be the total refund payment on the seven day cruise.

We can say X = 0, if there is no rain on all 7 days.

$P(X = 0) = _nC_x * P^x * (1 - P)n-x$

$P(X = 0) = _7C_o * 0.2^0 * (1-0.2)^{7-0$

$P(X = 0) =1 * 1* (1-0.2)^{7$

$P(X = 0) =(0.8)^{7$

$P(X = 0) =0.2097152$

If it rains on any one day; then X = 100

$P(X = 100) = _nC_x * P^x * (1 - P)n-x$

$P(X = 100) = _7C_1 * 0.2^1 * (1-0.2)^{7-1$

$P(X = 0) =7 * 0.2* (1-0.2)^{6$

$P(X = 100) =7* 0.2* (0.8)^{6$

$P(X = 100) =0.3670016$

if it rains on any two day ; then X = 200

$P(X = 200) = _nC_x * P^x * (1 - P)n-x$

$P(X = 200) = _7C_2 * 0.2^2 * (1-0.2)^{7-2$

$P(X = 200) = 21 * 0.2^2 * (0.8)^{5$

$P(X = 200) = 0.2752512$

if it rains on any three day or more than that ; then X = 300

$P(X \ge 300) = 1 - P(X < 300) \\ \\ P(X \ge 300) = 1 - [P(X = 0) + P(X = 100) + P(X = 200)] \\ \\ P(X \ge 300) = 1 - [0.2097152 + 0.3670016 + 0.2752512] \\ \\ P(X \ge 300) = 0.148032$

Now; we have our probability distribution function as:

P(X = 0) = 0.2097152

P(X = 100) = 0.3670016

P(X = 200) = 0.2752512

P(X = 300) = 0.148032

In order to determine the variance of the refund payment to the couple; we use the formula:

variance of the refund payment to the couple $[Var X] =E [X^2] - (E [X])^2$

where;

$E[X^2] = \sum x^2 \times p \\ \\ E[X^2] = 0^2 * 0.2097152 + 100^2 * 0.3670016 + 200^2 * 0.2752512 + 300^2 * 0.148032 \\ \\ E[X^2] = 0 + 3670.016 + 11010.048+ 13322.88 \\ \\ E[X^2] =28002.944$

$(E [X]) = \sum x * p\\ \\ (E [X]) = 0 * 0.2097152 + 100 * 0.3670016 + 200 * 0.2752512 + 300 * 0.148032 \\ \\ (E [X]) = 0 + 36.70016 + 55.05024 + 44.4096\\ \\ (E [X]) = 136.16 \\ \\ (E [X])^2 = 136.16^2 \\ \\ (E [X])^2 = 18539.55$

NOW;

the variance of the refund payment to the couple = 28002.944 - 18539.55

the variance of the refund payment to the couple = 9463.394

7 0

3 years ago

How much money has to be invested at 2.3% interest compounded continuously to have $41,000 after 17 years?

Llana [10]

For this, we have to calculate how much money has to be invested at 2.3% interest compounded continuously to achieve $41,000 after 17 years

Formula: A= P * ( 1+r)^t
A= $41,000
r=0.023
t= 17
<span>41,000= P * (1+0.023)^17
</span>41,000= P * (1.023)^17
41,000= P * 1.4719
P= 41,000 : 1.4719
P= $27,731.59
Therefore, the answer is C. $27,731.59
I checked by doing the opposite, and I got $41,000.01, which is the closest to the question<span>
</span>

7 0

3 years ago