Answer:
The equation of the circle is ![x^2 + (y + 3)^2 = 11](https://tex.z-dn.net/?f=x%5E2%20%2B%20%28y%20%2B%203%29%5E2%20%3D%2011)
Step-by-step explanation:
Equation of a circle:
The equation of a circle with center
and radius r is given by:
![(x - x_0)^2 + (y - y_0)^2 = r^2](https://tex.z-dn.net/?f=%28x%20-%20x_0%29%5E2%20%2B%20%28y%20-%20y_0%29%5E2%20%3D%20r%5E2)
Center (0, -3)
This means that ![x_0 = 0, y_0 = -3](https://tex.z-dn.net/?f=x_0%20%3D%200%2C%20y_0%20%3D%20-3)
Radius square root of 11
This means that ![r = \sqrt{11}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%7B11%7D)
Equation of the circle:
![(x - x_0)^2 + (y - y_0)^2 = r^2](https://tex.z-dn.net/?f=%28x%20-%20x_0%29%5E2%20%2B%20%28y%20-%20y_0%29%5E2%20%3D%20r%5E2)
![(x - 0)^2 + (y - (-3))^2 = (\sqrt{11})^2](https://tex.z-dn.net/?f=%28x%20-%200%29%5E2%20%2B%20%28y%20-%20%28-3%29%29%5E2%20%3D%20%28%5Csqrt%7B11%7D%29%5E2)
![x^2 + (y + 3)^2 = 11](https://tex.z-dn.net/?f=x%5E2%20%2B%20%28y%20%2B%203%29%5E2%20%3D%2011)
The equation of the circle is ![x^2 + (y + 3)^2 = 11](https://tex.z-dn.net/?f=x%5E2%20%2B%20%28y%20%2B%203%29%5E2%20%3D%2011)
Answer:
(1, 1), (2, 2), (-3, -3), (4, 4), (-5, -5)
Step-by-step explanation:
You get a straight line. As you can see in the picture, the figure lies in the first and third quadrant.
80 square units
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The Formula for the area of a trapezoid is A= (a+b/2)h
A= 3+17/2 (8)
A= 20/2 (8)
A= 10 (8)
A = 80
I’m not insert under damaging
Answer: A. (3x² + 4x-7)(x) + (3x² + 4x-7)(-2)
Step-by-step explanation:
The expressions are equivalent by the distributive property.