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3 years ago

Is PQRST a scaled copy of ABCDE ? Explain reasoning

Mathematics

1 answer:

loris [4]3 years ago

7 0

Answer: no

Step-by-step explanation:

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A bird flies from the bottom of a canyon that is 52

Assoli18 [71]

The difference in the elevation between the canyon and the bird's nest is 737. 3 feet

<h3>How to determine the value</h3>

From the information given, we have that;

The distance below the sea level = 52 3/ 5 feet , this would take a negative value
The distance above sea level = 789 3/ 10, this would take a positive value

Let's convert the mixed fractions to improper fraction;

= - 263/ 5 = - 52. 6 feet

789 3/ 10 = 7893/ 10 = 789. 3 feet

The difference in the elevation between the canyon and the bird's nest ;

= -52. 6 + 789. 9

= 737. 3 feet

Thus, the difference in the elevation between the canyon and the bird's nest is 737. 3 feet

Learn more about distance here:

brainly.com/question/7243416

#SPJ1

7 0

2 years ago

Two particles move in the xy-plane. At time t, the position of particle A is given by x(t)=5t−5 and y(t)=2t−k, and the position

Ipatiy [6.2K]

Answer:

Part A) Not collide

Part B) k = 4

Part C) Particle B is moving fast.

Step-by-step explanation:

Two particles move in the xy-plane. At time, t

Position of particle A:-

$x(t)=5t-5$

$y(t)=2t-k$

Position of particles B:-

$x(t)=4t$

$y(t)=t^2-2t+1$

Part A) For k = -6

Position particle A, (5t-5,2t+6)

Position of particle B, $(4t,t^2-2t-1)$

If both collides then x and y coordinate must be same

Therefore,

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t+6=t^2-2t-1$

$t^2-4t-7=0$

$t=-1.3,5.3$

The value of t is not same. So, k = -6 A and B will not collide.

Part B) If both collides then x and y coordinate must be same

For x-coordinate:

5t - 5 = 4t

t = 5

For y-coordinate:

$2t-k=t^2-2t-1$

Put t = 5

$10-k=25-10-1$

$k=4$

Hence, if k = 4 then A and B collide.

Part C)

Speed of particle A, $\dfrac{dA}{dt}$

$\dfrac{dA}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dA}{dt}=2\cdot \dfrac{1}{5}\approx 0.4$

Speed of particle B, $\dfrac{dB}{dt}$

$\dfrac{dB}{dt}=\dfrac{dy}{dt}\cdot \dfrac{dt}{dx}$

$\dfrac{dB}{dt}=2t-2\cdot \dfrac{1}{4}$

At t = 5

$\dfrac{dB}{dt}=10-2\cdot \dfrac{1}{4}=2$

Hence, Particle B moves faster than particle A

8 0

3 years ago

How many bits are in one dollar

denis-greek [22]

Bits? what are bits?

7 0

3 years ago

If the flare is launched with an initial velocity of 144 feet per second, find the height after 2 seconds. The answer is not 288

Rashid [163]

H= ut -16 t^2

h = 144(2) - 16 (4)

= 288 - 64 = 224

4 0

3 years ago

Perform the operation. (9x2 + 6x – 7) + (-9x - 5) PLS HELP ASAP PLS

qaws [65]

Answer:

Step-by-step explanation:

(9x2 + 6x – 7) + (-9x - 5) = 21

6 0

3 years ago

Read 2 more answers