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jeka94
3 years ago
11

What can a set of points tell you about a linear relationship?

Mathematics
1 answer:
hodyreva [135]3 years ago
3 0

Answer:

A linear relationship (or linear association) is a statistical term used to describe a straight-line relationship between two variables. Linear relationships can be expressed either in a graphical format or as a mathematical equation of the form y = mx + b.

Step-by-step explanation:

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an ice cream shop has a total of 48 flavors of ice cream and toppings. if there are 16 flavors of ice cream, how many toppings c
Tanzania [10]

Answer:

B

Step-by-step explanation:

There are 48 flavors and toppings. Since 16 are flavors, 32 are toppings. Dividing the 32 topping equally between 8 children is 4 toppings per child.

32 ÷ 8 = 4

3 0
3 years ago
100 POINTS, WILL MARK BRAINLIEST! If h(x) = f[f(x)] use the table of values for f and f ′ to find the value of h ′(1).
victus00 [196]

Answer:

The value of h^\prime(1)=5

Step-by-step explanation:

Given that  h(x)=f(f(x))

now to find h(x)=f(f(x)) from the given functions f(x) and f'x

let h(x)=f(f(x))

Then put x=1 in above function we get

h(1)=f(f(1))

=f(3) (from the table f(1)=3 and f(3)=6)

Therefore h(1)=6

Now to find h'(1)

Let

h^{\prime}(x)=f^{\prime}(f^\prime(x)) (since  h(x)=f(f(x)) )

put x=1 in above function we get

h^{\prime}(1)=f^{\prime}(f^\prime(1))

=f^{\prime}(2)    (From the table f^\prime(1)=2 and f^\prime(2)=5)

h^{\prime}(1)=5

Therefore h^{\prime}(1)=5

4 0
2 years ago
Read 2 more answers
A sequence is defined by the following: an = 4n – 1 What is a1?
Alexandra [31]

an = 4n – 1

a1  means n=1

a1 = 4(1) -1

a1 = 4-1

a1 =3

Answer: 3

6 0
3 years ago
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Find a formula for the nth term in this arithmetic sequence first term -2 common difference an=
malfutka [58]
The formula for the problem is: An = 8(n-1) - 2

3 0
1 year ago
Find the midpoint between two points on a coordinate plane whose coordinates are (5.7) and (-3, 1).
jok3333 [9.3K]

Answer:

(1,4)

Step-by-step explanation:

if~(x,y)~is~mid~point~of~(x_{1},y_{1})~and~ (x_{2},y_{2}~then\\x=\frac{x_{1}+x_{2}}{2} \\y=\frac{y_{1}+y_{2}}{2} \\x=\frac{5-3}{2} =\frac{2}{2}=1\\y=\frac{7+1}{2} =\frac{8}{2} =4

(x,y)→(1,4)

6 0
2 years ago
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