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Phoenix [80]
3 years ago
7

Find the 5th term of 8/9 ,-4/3 ,2​

Mathematics
1 answer:
Mama L [17]3 years ago
7 0

Answer:

\frac{9}{2}

Step-by-step explanation:

There is a common ratio r between consecutive terms in the sequence, that is

r = \frac{-\frac{4}{3} }{\frac{8}{9} } = \frac{2}{-\frac{4}{3} } = - \frac{3}{2}

This indicates the sequence is geometric.

To obtain the next term multiply the previous term by r, that is

a₄ = 2× - \frac{3}{2} = - 3

a₅ = - 3 × - \frac{3}{2} = \frac{9}{2}

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Answer:

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Step-by-step explanation:

\tt \cfrac{1}{2^{-2}x^{-3}y^5}

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Substitute ''x'' with '2' & 'y' with "-4":-

\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}

First let's solve \tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5

\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }

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Calculate exponents:- -4^5= -1024

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Remove parentheses, apply rule:- \tt a\left(-b\right)=-ab

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Divide numbers:-

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Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

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