3w + 8 - w = 4w - 2(w - 4)
is an identity
3w-w + 8 = 4w - 2w + 8
2w + 8 = 2w + 8
2w - 2w = 8 - 8
0 = 0
zero equal to zero implies that any value of w satisfies the statement 3w + 8 - w = 4w - 2(w - 4) hence it is an identity.

3 0

4 years ago

Read 2 more answers

F(x)= 3x - 4x2 +6x and g(x)= 5x +2x2 – 3x. What is f(x) g(x)?

goldenfox [79]

f(x)g(x) = 9x² + 10x - 16

<u>Step-by-step explanation:</u>

Step 1:

Given f(x) = 3x - 4 × 2 + 6x and g(x) = 5x + 2 × 2 - 3x

f(x) = 9x - 8

g(x) = 2x + 4

f(x)g(x) = (9x - 8)(2x + 4)

= 18x² + 36x - 16x -32

= 18x² + 20x - 32

= 9x² + 10x - 16

7 0

3 years ago

A geometric sequence is shown below.

mestny [16]

Answer:

An explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

Step-by-step explanation:

Given the geometric sequence

$-\frac{1}{2},\:-2,\:-8,\:-32,...$

A geometric sequence has a constant ratio, denoted by 'r', and is defined by

$f_n=f_1\cdot r^{n-1}$

Determining the common ratios of all the adjacent terms

$\frac{-2}{-\frac{1}{2}}=4,\:\quad \frac{-8}{-2}=4,\:\quad \frac{-32}{-8}=4$

As the ratio is the same, so

r = 4

Given that f₁ = -1/2

substituting r = 4, and f₁ = -1/2 in the nth term

$f_n=f_1\cdot r^{n-1}$

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

Thus, an explicit representation for the nth term of the sequence:

$f_n=-\frac{1}{2}\cdot \:4^{n-1}$

It means, option (B) should be true.

8 0

3 years ago