a two digit number is 6 more than 3 times its unit digits.find the number if the sum of its digits is 9

Mathematics

1 answer:

Murrr4er [49]3 years ago

3 0

Answer:

Step-by-step explanation:

We can start as expressing the number as 10x+y, where x is the 10's digit and y is the 1's digit. From here, you can set up the following equations:

10x+y=3y+6

x+y=9

You can subtract x from both sides of the second equation, and substitute the y value into the upper equation like so:

10x+(9-x)=3(9-x)+6

10x+9-x=27-3x+6

Combining like terms:

12x=24

x=2

y=7

The number is 27.

Hope this helps!

You might be interested in

7. What is the force of tension in a rope that spins a 250 g object in a vertical circle with a radius of 50 cm if the

Phantasy [73]

Subtract 250-50 which equals 200 and then multiply it by 3 which is 600

4 0

3 years ago

What is the first quartile (Q1) of the data set?

KATRIN_1 [288]

Sequence = 40, 45, 48, 51, 59, 62, 69, 74

Median = 51+59 / 2 = 55
First quartile = 40, 45, 48, 51
So, it would be: 45 + 48 / 2 = 46.5

In short, Your Answer would be Option C

Hope this helps!

8 0

3 years ago

Cos(-170°) = _____<br><br> -cos10°<br> cos10°<br> cos(-10°)

ikadub [295]

<em>The right answer for:</em>

<h2>Explanation:</h2>

The cosine function is an even function, which means that for every point $(x,y)$ on the graph of $y=cos(x)$ then the point $(-x,y)$ also lies on the graph of the function. In other words, we can write:

$cos(-170^{\circ})=cos(170^{\circ})$

But:

$170^{\circ}=180^{\circ}-10^{\circ}$

So:

$cos(170^{\circ})=cos(180^{\circ}-10^{\circ})$

By property:

$cos(a-b)=cosacosb+sinasinb \\ \\ a=180^{\circ} \\ \\ b=10^{\circ} \\ \\ cos(170^{\circ} )=cos(180^{\circ} -10^{\circ})=cos180^{\circ} cos10^{\circ} +sin180^{\circ} sin10^{\circ} \\ \\ cos(170^{\circ})=-cos(10^{\circ})+0 \\ \\ \boxed{cos(170^{\circ})=-cos(10^{\circ})}$