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tamaranim1 [39]
3 years ago
10

Adam had some candy to give to his three children. He first took seven pieces for himself and then evenly divided the rest among

his children. If Adam started with 13 pieces, how many did each child receive?
Mathematics
2 answers:
Katen [24]3 years ago
8 0
Adam took 7 pieces so subtract it from the total.
13 - 7 = 6
He divided the rest to his 3 children
\frac{6}{3}  = 2
Each child recieved 2 candies.
aalyn [17]3 years ago
6 0
First you do 13-7 since he already took those for himself. Now u have to divide 6, the remainder, by 3 since there are 3 children. 6 divided by 3 = 2

So each child received 2 pieces of candy
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Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
Easy math problems!!!!!
Alexandra [31]

Answer: 36

Step-by-step explanation:

7 0
3 years ago
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A town park has two biking trails. Marsh Trail is 5 3/10 miles long. Woodland trail is 2 4/5 Miles long. How much longer is Mari
torisob [31]

Answer:

21/2

Step-by-step explanation:

The answer can be determined by substracting the lengrh of the woodland trail from the Marsh trail

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expeople1 [14]

I think you can find it graphically by points through a table you create like:

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for example for the first equation when we let x = 0 you find y = 6 and be in the form of (0,6) then draw them or you can let x = -2 or -3 , etc as you like

to be more accurate you can find 3 pionts and start graphing them

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5 0
3 years ago
How do I solve this?
Sonbull [250]

The question is somewhat poorly posed because the equation doesn't involve <em>θ</em> at all. I assume the author meant to use <em>x</em>.

sec(<em>x</em>) = csc(<em>x</em>)

By definition of secant and cosecant,

1/cos(<em>x</em>) = 1/sin(<em>x</em>)

Multiply both sides by sin(<em>x</em>) :

sin(<em>x</em>)/cos(<em>x</em>) = sin(<em>x</em>)/sin(<em>x</em>)

As long as sin(<em>x</em>) ≠ 0, this reduces to

sin(<em>x</em>)/cos(<em>x</em>) = 1

By definition of tangent,

tan(<em>x</em>) = 1

Solve for <em>x</em> :

<em>x</em> = arctan(1) + <em>nπ</em>

<em>x</em> = <em>π</em>/4 + <em>nπ</em>

(where <em>n</em> is any integer)

In the interval 0 ≤ <em>x</em> ≤ 2<em>π</em>, you get 2 solutions when <em>n</em> = 0 and <em>n</em> = 1 of

<em>x</em> = <em>π</em>/4   <u>or</u>   <em>x</em> = 5<em>π</em>/4

5 0
2 years ago
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