Is the gcf os a pair of numbers ever greater than both numbers ? explain with an example.

2 answers:

6 0

The gcf of numbers can never be greater than both numbers, because in order to be a gcf, it must be a factor that both numbers have, so if one number does not have that then it is not a gcf.

VARVARA [1.3K]3 years ago

4 0

Answer:

No, G.C.F. of pair of numbers can never be greater than both numbers.

Step-by-step explanation:

G.C.F. (Greatest Common Factor) of pair of numbers is defined as the greatest factor of both the number that exactly divides both numbers.

For Example: G.C.F. of 14 and 21 =

36 = 2 × 2 × 3 × 3

48 = 2 × 2 × 2 × 2 × 3

Common Factors of 36 and 48 = 2 × 2 × 3 = 12

∴ G.C.F. = 12

As, we see that G.C.F. is factor of given number. So, it can never be greater than given numbers.

You might be interested in

Solve for m: (y_1 - y_2) = m(x_1 - x_2)

Mashutka [201]

$y_1-y_2=m(x_1-x_2)\\
m=\dfrac{y_1-y_2}{x_1-x_2}$

5 0

3 years ago

Evaluate the expression when x= -4. 2 x + 6x+9

ExtremeBDS [4]

Answer:

The answer is -23.

Step-by-step explanation:

substitute x with -4. multiply and add regularaly.

6 0

2 years ago

Read 2 more answers

A. The point-slope form of the equation of a line is y ? y1 = m(x ? x1), where m is the slope and (x1, y1) is a point on the lin

Rudiy27

Answer:

$y - 5 = -2(x-6)$

Negative reciprocal gives you the perpendicular slope so negative reciprocal of 1/2 is -2.

Then apply point-slope form.

B. The answer is x = 6.

The midpoint of JK is

$\left( \frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2} \right) = \left( \frac{8+ 4}{2}, \frac{4 + 4}{2} \right) = \left(6,4\right)$

The line that goes through JK is just a horizontal line $y = 4$ because the y-coordinate does not change. So its perpendicular bisector is the vertical line that goes through the x-coordinate of the midpoint, that is, $x = 6$ .